Question

The junior class has 50 students. Twenty-five students take only french, 15 take only Latin, and 10 take both. If a student is chosen at random from the class, what is the probability that the student takes latin?
A.)1
B.)1/2
C.)
1/4

Answer 1

Answer: B ) $\frac{1}{2}$

Step-by-step explanation:

Given: The number of students in junior class n(S)= 50

The number of students take only Latin n(L-F)= 15

The number of students take only French n(F-L)=25

The number of students take both = n(F∩L)=10

The number of students take Latin n(L)=n(L-F)+n(F∩L)=15+10=25

Therefore, the probability that the student takes Latin is given by :-

$\text{Probability(Latin)}=\frac{\text{number of students take latin}}{\text{Total students}}\\\\=\frac{25}{50}=\frac{1}{2}$

Answer 2

There are 15 students who take Latin, and 10 students who take both.
Therefore:
15+10 =25 total students taking Latin
25students / 50 total students = 1/2

The answer is 1/2.