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3 years ago

A circle is centered at (−4, −6) and has a radius of 3. Which of the following is the equation for this circle? (6 points)

Mathematics

2 answers:

liraira [26]3 years ago

8 0

Answer:

The equation of circle is $(x+4)^2+(y+6)^2=9$ .

Step-by-step explanation:

Given information:

Center of circle = (-4,-6)

Radius of circle = 3 units

The standard equation of a circle is

$(x-h)^2+(y-k)^2=r^2$ .... (1)

where, (h,k) is center of the circle and r is radius.

Substitute h=-4, k=-6 and r=3 in equation (1), to find the standard form of the given circle.

$(x-(-4))^2+(y-(-6))^2=(3)^2$

$(x+4)^2+(y+6)^2=9$

Therefore the equation of circle is $(x+4)^2+(y+6)^2=9$ .

ANTONII [103]3 years ago

6 0

$\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{-4}{ h},\stackrel{-6}{ k})\qquad \qquad 
radius=\stackrel{3}{ r}
\\\\\\\
[x-(-4)]^2+[y-(-6)]^2=3^2\implies (x+4)^2+(y+6)^2=9$

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Given

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