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german
4 years ago
9

David charges $4 to wash all the windows of a car, inside and out. The amount of money he earns washing the windows must end in

one of what digits? Why? List all the possible digits.
Mathematics
1 answer:
nordsb [41]4 years ago
4 0

Answer:

The possible digits are : 0, 2, 6, 4, 8

Step-by-step explanation:

Money charged by David to wash the windows of a car = $4

Let total number of cars he washed be x

Now, Total money earned by washing windows of a car = Money charged for washing all windows of one car × Total number of cars washed

⇒ Total money earned = 4 × x

So, the amount will always end in the digits which comes at the end of multiples of 4 because the amount will be always in the multiples of 4

⇒ 4 × 1 = 4 , 4 × 2 = 8 , 4 × 3 = 12 , 4 × 4 = 16 , 4 × 5 = 20 ......

So, the possible digits are : 0, 2, 6, 4, 8

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Which expressions have a value of -64? Check all that apply. NEED HELP ASAP PLSSS!!!
ziro4ka [17]

Answer: -(1/4)^3

Step-by-step explanation:

Equals -1/64 which is -64

6 0
3 years ago
Suppose two random variables, X and Y are independent, which statement is false? a) P(X∣Y)=P(X) b) P(X∪Y)=P(X)+P(Y) c) P(X∩Y)=P(
Svetlanka [38]

B is false, since by the inclusion/exclusion principle,

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)

By independence, we have P(X\cap Y)=P(X)P(Y), which is zero if either of P(X) or P(Y) is 0, which isn't guaranteed.

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3 years ago
Suppose it is known that 60% of radio listeners at a particular college are smokers. A sample of 500 students from the college i
vladimir1956 [14]

Answer:

The probability that at least 280 of these students are smokers is 0.9664.

Step-by-step explanation:

Let the random variable <em>X</em> be defined as the number of students at a particular college who are smokers

The random variable <em>X</em> follows a Binomial distribution with parameters n = 500 and p = 0.60.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

1. np ≥ 10

2. n(1 - p) ≥ 10

Check the conditions as follows:

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Thus, a Normal approximation to binomial can be applied.

So,  

X\sim N(\mu=600, \sigma=\sqrt{120})

Compute the probability that at least 280 of these students are smokers as follows:

Apply continuity correction:

P (X ≥ 280) = P (X > 280 + 0.50)

                   = P (X > 280.50)

                   =P(\frac{X-\mu}{\sigma}>\frac{280-300}{\sqrt{120}}\\=P(Z>-1.83)\\=P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that at least 280 of these students are smokers is 0.9664.

8 0
3 years ago
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Aleksandr [31]

Answer:

Step-by-step explanation:

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Mark up price = selling price- cost price

= (20% × $n)

Selling price = $n + (20% × $n)

Sales tax = 5% × ($n + (20% × $n))

Total cost = selling price + sales tax

Total cost = $n + (20% × $n) + 5% × $n + (20% × $n)

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8 0
3 years ago
Products equivalent to the quotient of 9/ divided by 2
Murljashka [212]

Answer:

\frac{3}{\sqrt{2} }^2

Step-by-step explanation:

8 0
3 years ago
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