<h3>
Answer ↓</h3>
<h3>
Calculations ↓</h3>
In order to make a the subject of this equation , we need to get a by itself .
The current equation is :
v = u + at
Subtract u on both sides :
v-u=at
Now, divide by t on both sides :
v-u/t=a
<h3>So the formula looks like ↓</h3>
hope helpful ~
Answer:
The two horiz. tang. lines here are y = -3 and y = 192.
Step-by-step explanation:
Remember that the slope of a tangent line to the graph of a function is given by the derivative of that function. Thus, we find f '(x):
f '(x) = x^2 + 6x - 16. This is the formula for the slope. We set this = to 0 and determine for which x values the tangent line is horizontal:
f '(x) = x^2 + 6x - 16 = 0. Use the quadratic formula to determine the roots here: a = 1; b = 6 and c = -16: the discriminant is b^2-4ac, or 36-4(1)(-16), which has the value 100; thus, the roots are:
-6 plus or minus √100
x = ----------------------------------- = 2 and -8.
2
Evaluating y = x^3/3+3x^2-16x+9 at x = 2 results in y = -3. So one point of tangency is (2, -3). Remembering that the tangent lines in this problem are horizontal, we need only the y-coefficient of (2, -3) to represent this first tangent line: it is y = -3.
Similarly, find the y-coeff. of the other tangent line, which is tangent to the curve at x = -8. The value of x^3/3+3x^2-16x+9 at x = -8 is 192, and so the equation of the 2nd tangent line is y=192 (the slope is zero).
Answer:
Step-by-step explanation:
1. 3x2 + 5x - 4 + 6x2 - x + 7
= combining like terms
= 9x2 + 4x + 3
2. 2y2 - 3y + 6 + y2 - 5y - 1 + (-4) + 2y2 - 2y
= 5y2 - 10y + 1
3. 2x2y - 3xy2 + x2y - 4x2y - 2xy2
= - x2y - 5xy2
4. x2 - y2 + 2x2 - 3xy + 4y2 + 3y2 - 5xy - x2
= 2x2 - 8xy + 6y2
Answer:
-9.56
Step-by-step explanation:
Answer:
20000
Step-by-step explanation:
13000/.65=20000
