Answer:
![m\angle Y=40^\circ](https://tex.z-dn.net/?f=m%5Cangle%20Y%3D40%5E%5Ccirc)
Step-by-step explanation:
Suppose we have a triangle WXY whose internal angles are:
![m\angle W = 10x+17](https://tex.z-dn.net/?f=m%5Cangle%20W%20%3D%2010x%2B17)
![m\angle X=2x-9](https://tex.z-dn.net/?f=m%5Cangle%20X%3D2x-9)
![m\angle Y=3x+7](https://tex.z-dn.net/?f=m%5Cangle%20Y%3D3x%2B7)
The sum of the measures of the angles must be 180°, thus:
![10x+17 + 2x-9+3x+7=180](https://tex.z-dn.net/?f=10x%2B17%20%2B%202x-9%2B3x%2B7%3D180)
Simplifying:
15x + 15 = 180
Subtracting 15:
15x = 165
Dividing by 15:
x = 11
Thus, the measure of angle Y is
![m\angle Y=3x+7=3*11+7=33+7=40](https://tex.z-dn.net/?f=m%5Cangle%20Y%3D3x%2B7%3D3%2A11%2B7%3D33%2B7%3D40)
![\mathbf{m\angle Y=40^\circ}](https://tex.z-dn.net/?f=%5Cmathbf%7Bm%5Cangle%20Y%3D40%5E%5Ccirc%7D)
Answer:
I did the whole graph myself so you can just couple it down lol ;)
If the smaller number is x, then the larger number has to be 20 - x in order for the arithmetic mean to be 10, as their sum must be 20.
If the geometric mean is 8 the product of the numbers has to be 64 and so the larger number is 64/x
Solving 64/x = 20 - x gives the quadratic x^2 -20x +64 = 0 so x = 4 or 16.
The two numbers are 4 and 16.