Answer:
c. f(x) x+1/x-1
Step-by-step explanation:
To answer this question, we need to check each answer one by one until we find the right one.
y = (x+6)/(x-6)
switch x and y
x = (y+6)/(y-6)
solve for y
x(y-6) = y+6
xy - 6x = y+6
y(x-1) = 6x+6
y = (6x+6) /(x-1) = 6(x+1)/(x-1)
f^-1(x) = 6(x+1)/(x-1)
y = (x+2)/(x-2)
switch x and y
x = (y+2)/(y-2)
solve for y
x(y-2) = y+2
xy -2x = y+2
y(x-1) = 2x+2
y = (2x+2)/(x-1)
f^-1(x) = 2(x+1)/(x-1)
y = (x+1)/(x-1) ------ correct one
switch x and y
x = (y+1)/(y-1)
solve for y
x(y-1) = y+1
xy - x = y+1
y(x-1) = x+1
y = (x+1)/(x-1)
f^-1(x) = (x+1)/(x-1)
f(x) = f^-1(x)
Answer:
144 i think
Step-by-step explanation:
Answer:
When AB coincides with AC, the boundary of EAF maps exactly onto the boundary of CAD, implying that EAF dilates into CAD. So, the boundaries of EAF and CAD are similar.
The proportional relationship may be stated in different forms, but should be equivalent to this equation:
radius of Ab/ radius of Ac= length of arc EF/ length of arc CD
Explanations will vary, but should be based on the similarity of EAF and CAD. The proportional relationship follows from the fact that corresponding pairs of lengths in two similar figures have the same ratio.
Step-by-step explanation:
This is the exact answer so make sure you change it up a little.
