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Allisa [31]
2 years ago
6

Suppose Cotangent (theta) = StartFraction 5 Over 12 EndFraction, where Pi less-than theta less-than StartFraction 3 pi Over 2 En

dFraction. What is sin(θ)?
Negative StartFraction 12 Over 13 EndFraction
Negative StartFraction 5 Over 13 EndFraction
StartFraction 5 Over 13 EndFraction
StartFraction 12 Over 13 EndFraction
Mathematics
1 answer:
Agata [3.3K]2 years ago
5 0

Answer:

Sin theta = 12/13

Step-by-step explanation:

From the question;

Cot theta = 5/12

Kindly recall;

Cot theta = 1/ tan theta

Hence, tan theta = 12/5

Mathematically

tan theta= opposite/adjacent

to get hypotenuse, we will use Pythagoras’ theorem which states that the square of the hypotenuse equals sum of the squares of the two other sides

let hypotenuse be h

h^2 = 12^2 + 5^2

h^2 = 144 + 25

h^2 = 169

h = √169

h = 13

But sine theta = opposite/ hypotenuse = 12/13

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Are 12:14 and 60:70 equivalent ratios?<br><br> yes<br> no
NNADVOKAT [17]

Answer:

Yes, they are equalent

Step-by-step explanation:

12:14 = 6:7

60:70 =6:7

both can be simplified to 6:7

5 0
3 years ago
Solve the equation for k. -11 = 7 + 2/3k<br><br> A. -24<br> B. -25<br> C. -26<br> D. -27
Kryger [21]

Answer:

k= -27

step-by-step

8 0
2 years ago
10. If possible, determine whether or not triangles LQP and LMN
natita [175]

Answer:

They are similar

Step-by-step explanation:

If two triangles are similar, the ratio of their corresponding side lengths must be equal to each other.

This means that for ∆LQP and ∆LMN to be considered similar to each other, therefore:

LM/LQ = LN/LP

LM = 100

LQ = 12

LN = 75

LP = 9

LM/LQ = 100/12 = 25/3

LN/LP = 75/9 = 25/3

LM/LQ = LN/LP = 25/3, therefore ∆LQP and ∆LMN are similar to each other because the ratio of their corresponding side lengths are the same.

3 0
2 years ago
Show that 3x^2 -2x + 1 is always greater than 0.<br> ( This is an Additional Math Question )
Leviafan [203]

Answer:

3x^2 -2x + 1 =3(x^2-2/3x+1/3)=3(x-1/3)^2+2/9*3= 3(x-1/3)^2+2/3

(x-1/3)^2 is greater or equal to zero

3(x-1/3)^2 is greater or equal to zero

and 2/3 is greater than zero

So there sum is greater than zero

Proved

Step-by-step explanation:

3x^2 -2x + 1 =3(x^2-2/3x+1/3)

Consider x^2-2/3x+1/3

Remember that (a-b)^2 =a^2-2ab+b^2

x^2=a^2

a=x

-2/3x= -2*x*b

b=1/3

S0 (x-1/3)^2= x^2-2/3x+1/9

x^2-2/3x+1/3= x^2-2/3x+1/9+1/3-1/9= (x-1/3)^2+2/9

3x^2 -2x + 1 =3(x^2-2/3x+1/3)=3(x-1/3)^2+2/9*3= 3(x-1/3)^2+2/3

(x-1/3)^2 is greater or equal to zero

3(x-1/3)^2 is greater or equal to zero

and 2/3 is greater than zero

So there sum is greater than zero

Proved

6 0
3 years ago
An oblique square prism is shown. Which expression represents the volume of the prism?
Furkat [3]

Answer:

C. x^2*(x-2)\text{ Cubic units}

Step-by-step explanation:

We have been given a diagram of an oblique prism and we are asked to choose the expression that represents the volume of the prism.

Since we know that an oblique prism is a prism in which the bases are parallel, but the faces are not directly one over the other.

The volume of an oblique prism is base area multiplied by the height.

\text{Volume of an oblique prism}=\text{Base area* Height of the prism}

We can see from our diagram that our prism has an square base as each side of base equals x units.

\text{Base area of prism}=x\text{ units}*x\text{ units}

\text{Base area of prism}=x^2\text{ units}^2

We can also see from our given diagram that it has a height of (x-2) units and slant height of (x+1) units.  

Since volume of oblique prism is base area times by the height (not slant height). So upon substituting the height and base area of our given prism in volume formula we will get,

\text{Volume of an oblique prism}=x^2\text{ units}^2*(x-2)\text{ units}

\text{Volume of an oblique prism}=x^2*(x-2)\text{ units}^3

Therefore, the volume of our given prism is x^2*(x-2)\text{ Cubic units} and option C is the correct choice.

3 0
3 years ago
Read 2 more answers
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