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2 years ago

$1, 000 after 2 years at an interest rate of 3.0% is $ round up to the nearest cent

1 answer:

5 0

This may be a simple interest computation.

Simple Interest = Principal * interest rate * term

Principal = 1,000
interest rate = 3%
term = 2 years

Simple Interest = 1,000 * 0.03 * 2
Simple Interest = 60

Total Amount after 2 years: 1,000 + 60 = 1,060

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Ivory created a scaled copy of rectangle A.

9966 [12]

The scale factor that Ivory used to create their scaled copy is;

Scale is 1 interval on graph represents 4 units of the rectangle. This is 1:4 ratio.

From the given image, we can see that the y-axis of the rectangle has 3 intervals while the x-axis has 1 intervals

Now, from the image, we are told that the area of the scaled copy is 48 square units.

What this means is that the area of the triangle she is trying to represent with that graph is 48 square units.

Now, if one interval of the graph is x-units, then it means;

length; y-axis = 3x units

width; x-axis = x units

Area of a rectangle is given by;

Area = Length × width

Thus;

3x * x = 48

3x² = 48

x² = 48/3

x² = 16

x = √16

x = 4

Thus, 1 interval on the graph represents 4 units of the rectangle.

Read more at; brainly.com/question/17182684

8 0

1 year ago

Will mark Brainlyest

Dima020 [189]

Answer:

Step-by-step explanation:

10 workers working 2 hours a day is 2*10=20 work hours per day

2 workers working 5 hours a day is 2 *5=10 work hours per day

Per day 1/2 as many work hours so will take 2 times as long.

5*2 = 10 days

7 0

3 years ago

Read 2 more answers

Find all the zeros of the polynomial function p(x) = x3 – 5x2 + 33x – 29

hram777 [196]

Answer:

$\large \boxed{\sf \ \ x=1, \ \ x=2+5i, \ \ x=2-5i \ \ }$

Step-by-step explanation:

Hello,

I assume that we are working in $\mathbb{C}$ , otherwise there is only one zero which is 1. Please consider the following.

First of all, we can notice that 1 is a trivial solution as

$p(1) = 1^3-5\cdot 1^2 + 33\cdot 1-29=1-5+33-29=0$

It means that (x-1) is a factor of p(x) so we can find two real numbers, a and b, so that we can write the following.

$p(x)=(x-1)(x^2+ax+b)=x^3+ax^2+bx-x^2-ax-b=x^3+(a-1)x^2+(b-a)x-b$

Let's identify like terms as below.

a-1 = -5 <=> a = -5 + 1 = -4

b-a = 33

-b = -29 <=> b = 29

$\boxed{ \ p(x)=(x-1)(x^2-4x+29) \ }$

Now, we need to find the zeroes of the second factor, meaning finding x so that:

$x^2-4x+29=0 \ \text{ complete the square, 29 = 25 + 4} \\ \\ x^2-2\cdot 2 \cdot x+2^2+25=0 \\ \\ (x-2)^2=-25=(5i)^2 \ \text{ take the root } \\ \\x-2=\pm 5i \ \text{ add 2 } \\ \\ x = 2+5i \ \text{ or } \ x = 2-5i$