All categories

3 years ago

Help me I am stuck in math!!!!!!

Mathematics

2 answers:

almond37 [142]3 years ago

5 0

Answer:

4 years

Step-by-step explanation:

Interest (I) = $ 100

r = 3.8 %

P = $ 700

t = ?

$t = \frac{I *100}{P*r}\\\\t = \frac{100 * 100}{700 * 3.8}\\\\t = \frac{100 * 100}{70 * 38}\\\\t = 3.75$

t = 4 years

Archy [21]3 years ago

4 0

I’m bad at math too sorry i can’t helppp i just need to answer one to ask a question

You might be interested in

Ken is thinking of a number. Nine more than the product of 4 and the number is 73. Find Ken number

Sliva [168]

----------------------------------------
Define x :
----------------------------------------
Let the number be x.

----------------------------------------
Construct equation:
----------------------------------------
<span>Nine more than the product of 4 and the number is 73
</span>⇒4x + 9 = 73

----------------------------------------
Solve for x:
----------------------------------------
4x + 9 = 73
4x = 73 -9
4x = 64
x = 16

----------------------------------------
Answer: Ken's number is 16.
----------------------------------------

7 0

4 years ago

The edge of a cube was found to be 30 cm with a possible error in measurement of 0.2 cm. Use differentials to estimate the maxim

rjkz [21]

Answer:

Maximum volume error = ±540 cm³

Relative error = 0.02

Percentage error = 2%

Step-by-step explanation:

Relative error : The ratio of volume error to the total volume.

Percentage error: The product of relative error and 100.

The volume of a cube is = $side^3$

v =x³

Differentiate with respect to x

$\frac{dv}{dx} = 3x^2$

$\Rightarrow dv = 3x^2 dx$

Here are x = 30 cm and dx= ±0.2 cm

∴ dv = 3×(30 cm)² (±0.2 cm)

=±540 cm³

The volume of the cube = 30³ cm ³ = 27,000 cm³

Then the relative error

$=\frac{dv}{v}$

$=\frac{540 cm^3}{27,000 cm^3}$

= 0.02.

The percentage error

= (0.02×100)

=2%

7 0

3 years ago

There are 250 wolves in a national park. the wolf population is increasing at a rate of 16% per year. write an exponential model

Helga [31]

$\qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &250\\ r=rate\to 16\%\to \frac{16}{100}\dotfill &0.16\\ t=\textit{elapsed time} \end{cases} \\\\\\ A=250(1 + 0.16)^{t}\implies A=250(1.16)^t \\\\[-0.35em] ~\dotfill$

$A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\dotfill &1000\\ P=\textit{initial amount}\dotfill &250\\ r=rate\to 16\%\to \frac{16}{100}\dotfill &0.16\\ t=\textit{elapsed time} \end{cases} \\\\\\ 1000=250(1.16)^t\implies \cfrac{1000}{250}=1.16^t\implies 4=1.16^t \\\\\\ \log(4)=\log(1.16^t)\implies \log(4)=t\log(1.16) \\\\\\ \cfrac{\log(4)}{\log(1.16)}=t\implies \stackrel{\textit{about 9 years and 4 months}}{9.34\approx t}$