All categories

2 years ago

Mr. Smith had 34 of a peach pie left over. He split the leftover pie among his 3 co-workers.

Mathematics

1 answer:

viktelen [127]2 years ago

8 0

Answer:

11.333 infinity

Step-by-step explanation:

when you divide 34 by 3 you then get 11.3 infinity which would also be a repeating decimal

You might be interested in

(X-2) is a factor of x^4+2x^3-7x^

zysi [14]

Answer:

x−2x4+2x3−7x2−8x+12=x3+4x2+x−6

The rational root theorem suggests that other possible roots may be -6, 6, -3, 3, -2, 2, -1, and 1. It turns out that x=-2x=−2 is a root, since (-2)^3+4(-2)^2+(-2)-6=0(−2)3+4(−2)2+(−2)−6=0 , so x+2x+2 is also a factor and we have

\dfrac{x^4+2x^3-7x^2-8x+12}{(x-2)(x+2)}=x^2+2x-3(x−2)(x+2)x4+2x3−7x2−8x+12=x2+2x−3

Finally, we can factorize the remaining quotient easily:

x^2+2x-3=(x+3)(x-1)x2+2x−3=(x+3)(x−1)

so the other factors are x+2x+2 , x+3x+3 , and x-1x−1 .

6 0

2 years ago

$5 deduction plus $2 deposit plus $5 deposit is

alukav5142 [94]

Answer: The answer is 12

Step-by-step explanation: because 5+5+2=12.

6 0

2 years ago

Which of the following inequali

Maru [420]

Answer:

3<5

Step-by-step explanation: dont see a picture but i have an example

3 0

3 years ago

What is 64 thousandths in decimal form

shusha [124]

I am pretty sure it is 0.064. Hope this helps

8 0

2 years ago

Read 2 more answers

Suppose that an insect population’s density, in thousands per acre, during year n, can be modeled by the recursive formula: a1 =

vlabodo [156]

Answer:

The population alternates between increasing and decreasing

Step-by-step explanation:

<u><em>The options of the question are</em></u>

A) The population density decreases each year.

B) The population density increases each year.

C) The population density remains constant.

D) The population alternates between increasing and decreasing

we have

$a_n=2.9(a_n_-_1)-0.2(a_n_-_1)^2$

$a_1=8$

Find the value of $a_2$

For n=2

$a_2=2.9(a_1)-0.2(a_1)^2$

$a_2=2.9(8)-0.2(8)^2=10.4$

Find the value of $a_3$

For n=3

$a_3=2.9(a_2)-0.2(a_2)^2$

$a_3=2.9(10.4)-0.2(10.4)^2=8.528$

For n=4

$a_4=2.9(a_3)-0.2(a_3)^2$

$a_4=2.9(8.528)-0.2(8.528)^2=10.1858$

For n=5

$a_5=2.9(a_4)-0.2(a_4)^2$

$a_5=2.9(10.1858)-0.2(10.1858)^2=8.7887$

therefore

The population alternates between increasing and decreasing

7 0

2 years ago

Read 2 more answers