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3 years ago

All of the following statements about learning are true EXCEPT __

1 answer:

3 0

Craming last minute can lead to unecessary confusion however most examinars dont allow asking questions during exam

So if asking questions for clarification is allowed. A) is the odd one out

And these options are rather for test taking than learning

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Please answer this question correctly for 24 points and brainliest!!

amm1812

Answer:

$110

Step-by-step explanation:

Let a, b, and c represent the earnings of Alan, Bob, and Charles. The problem statement tells us ...

a + b + c = 480 . . . . . . the combined total of their earnings

-a + b = 40 . . . . . . . . . . Bob earned 40 more than Alan

2a - c = 0 . . . . . . . . . . . Charles earned twice as much as Alan

Adding the first and third equations, we get ...

(a + b + c) + (2a - c) = (480) + (0)

3a + b = 480

Subtracting the second equation gives ...

(3a +b) - (-a +b) = (480) -(40)

4a = 440 . . . . . . . . simplify

a = 110 . . . . . . . . . . divide by the coefficient of a

Alan earned $110.

_____

Check

Bob earned $40 more, so $150. Charles earned twice as much, so $220.

The total is then $110 +150 +220 = $480 . . . . as required

8 0

3 years ago

I’m confused on this one

Lisa [10]

The angle x is half the sum of the intercepted arcs, PQ and NO.

... (1/2)(65° + 45°) = 55° = x° = m∠PMQ

3 0

3 years ago

What is Limit of StartFraction StartRoot x + 1 EndRoot minus 2 Over x minus 3 EndFraction as x approaches 3?

scoray [572]

Answer:

$\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} = \boxed{ \frac{1}{4} }$

General Formulas and Concepts:

Calculus

Limits

Limit Rule [Variable Direct Substitution]:
$\displaystyle \lim_{x \to c} x = c$

Special Limit Rule [L’Hopital’s Rule]:
$\displaystyle \lim_{x \to c} \frac{f(x)}{g(x)} = \lim_{x \to c} \frac{f'(x)}{g'(x)}$

Differentiation

Derivatives
Derivative Notation

Derivative Property [Addition/Subtraction]:
$\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$
Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:
$\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

Identify given limit.

$\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3}$

Step 2: Find Limit

Let's start out by directly evaluating the limit:

[Limit] Apply Limit Rule [Variable Direct Substitution]:
$\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} = \frac{\sqrt{3 + 1} - 2}{3 - 3}$
Evaluate:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \frac{\sqrt{3 + 1} - 2}{3 - 3} \\& = \frac{0}{0} \leftarrow \\\end{aligned}$

When we do evaluate the limit directly, we end up with an indeterminant form. We can now use L' Hopital's Rule to simply the limit:

[Limit] Apply Limit Rule [L' Hopital's Rule]:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\\end{aligned}$
[Limit] Differentiate [Derivative Rules and Properties]:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \leftarrow \\\end{aligned}$
[Limit] Apply Limit Rule [Variable Direct Substitution]:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \\& = \frac{1}{2\sqrt{3 + 1}} \leftarrow \\\end{aligned}$
Evaluate:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \\& = \frac{1}{2\sqrt{3 + 1}} \\& = \boxed{ \frac{1}{4} } \\\end{aligned}$

∴ we have evaluated the given limit.

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Learn more about limits: brainly.com/question/27807253

Learn more about Calculus: brainly.com/question/27805589

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Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

3 0

1 year ago

Matt buys an item with a normal price of $25 and uses a 10% off cupon. How much does he save by using the coupon?

Anika [276]

By using this coupon he will save $2.50. You have to multiply 25 by 0.10.

7 0

3 years ago

Read 2 more answers

Which is the better buy, 6 bagels for $3.29 or 8 bagels for $4.15?

castortr0y [4]

Well, we'd want to calculate the price of 1 bagel first.

To see which is better: divide $3.29 by 6 and then divide $4.15 by 8 and see which has the lowest answer.

The first option rounds off to $0.55 for one bagel. The second option rounds off to $0.52 for one bagel.

The second option is the best.

7 0

3 years ago