The giving functions are from dofferent types. transforming a function does not change it's type so it is impossible to transfer f(x)=2 to f(x)=(x-3)^2-1.
Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
Answer:
-2
Step-by-step explanation:
the y-intercept is -2
Answer:
The second one, -11/12
Step-by-step explanation:
I used a website so sorry I don't have an explanation
