Is there like some kind of picture
8x5=40
So the car is 40 inches long
Answer:
30.17feet high
Step-by-step explanation:
Given the following
the distance from the base of the pole to the tip of the shadow = 49feet (hypotenuse)
angle of elevation = 38°
Required
Height of the flagpole (opposite)
Using the SOH CAH TOA identity
Sin theta = opposite/hypotenuse
Sin 38 = H/49
H = 49sin38
H = 49(0.6157)
H = 30.17feet
Hence the flagpole is 30.17feet high
Answer:
C: 3 root 3
Step-by-step explanation:
got it right on edge
I got 6.3 not sure if Im right
