9. One box has a surface area of 96 cm2 and a height of 4 cm.

0. What are the means of the following proportion? 3⁄15 = 12⁄60 A. 15 and 12 B. 3 and 15 C. 3 and 60 D. 12 and 60

Neko [114]

3 and 60." The means of the proportion is 15 and 12.

4 0

2 years ago

Find the arc length of the partial circle. <br>length is 1.<br>**See attached photo**<br>

KatRina [158]

Arc length of the quarter circle is 1.57 units.

Solution:

Radius of the quarter circle = 1

Center angle (θ) = 90°

To find the arc length of the quarter circle:

$$\text{Arc length}=2 \pi r\left(\frac{\theta}{360^\circ}\right)$

$$=2 \times 3.14 \times 1\left(\frac{90^\circ}{360^\circ}\right)$

$$=2 \times 3.14 \times 1\left(\frac{1}{4}\right)$

Arc length = 1.57 units

Arc length of the quarter circle is 1.57 units.

5 0

3 years ago

Sandra exerci 2/3 hours every day for two weeks while she was on vacation how many hours did Sandra exercise during her vacation

vagabundo [1.1K]

I think the us 1 1/3. 2/3 x 2/1=4/3=1 1/3. Hope it helps and I hope it right.

3 0

2 years ago

According to an article in Newsweek, the natural ratio of girls to boys is 100:105. In China, the birth ratio is 100:114 (46.7%

mojhsa [17]

Answer:

$z=\frac{0.42 -0.467}{\sqrt{\frac{0.467(1-0.467)}{150}}}=-1.154$

$p_v =2*P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of girls born is not significantly different from 0.467

Step-by-step explanation:

Data given and notation

n=150 represent the random sample taken

X=63 represent the number of girls born

$\hat p=\frac{63}{150}=0.42$ estimated proportion of girls born

$p_o=0.467$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion if girls is 0.467.:

Null hypothesis: $p=0.467$

Alternative hypothesis: $p \neq 0.467$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.42 -0.467}{\sqrt{\frac{0.467(1-0.467)}{150}}}=-1.154$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of girls born is not significantly different from 0.467

3 0

2 years ago

Which points did you include in your response? Check all that apply

iogann1982 [59]

Answer:

any of them work

Step-by-step explanation:

8 0

2 years ago