Secants P N and L N intersect at point N outside of the circle. Secant P N intersects the circle at point Q and secant L N inter
2 answers:
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Answer:
θ = -33.69°
Step-by-step explanation:
For Φ>0 and Φ<0 (in general Φ≠nπ where n is an integer), sin(Φ) ≠ 0
Dividing both equations:
Therefore:
arctan(θ) = -2/3
θ = -33.69°
The answer does not depend on the sign of Φ, in fact we just need that the sine does not become zero, which occurs when Φ is equal to an integer times π (radians) or 180 (degrees)
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Points that are given on x+y=4 are (0,4),(3,1) and (4,0) and points that are give for x-y=2 are (0,-2),(2,0) and (3,1)
