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Crazy boy [7]
3 years ago
12

Secants P N and L N intersect at point N outside of the circle. Secant P N intersects the circle at point Q and secant L N inter

sects the circle at point M. The length of P N is 32, the length of Q N is x, the length of L M is 22, and the length of M N is 14. In the diagram, the length of the external portion of the secant segment PN is . The length of the entire secant segment LN is . The value of x is .
Mathematics
2 answers:
JulijaS [17]3 years ago
7 0

Answer:

A circle is shown. Secants P N and L N intersect at point N outside of the circle. Secant P N intersects the circle at point Q and secant L N intersects the circle at point M. The length of P N is 32, the length of Q N is x, the length of L M is 22, and the length of M N is 14.

In the diagram, the length of the external portion of the secant segment PN is <u>X</u>

The length of the entire secant segment LN is <u>36</u>.

The value of x is <u>15.74</u>

Step-by-step explanation:

Snap

Jona_Fl16

solmaris [256]3 years ago
7 0

Answer:

In the diagram, the length of the external portion of the secant segment PN is x. The length of the entire segment LN is 36. The value of x is 17.75.

Step-by-step explanation:

I just did it on Edge.

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Answer:

The mass of the object is 2.6 grams

Step-by-step explanation:

The density of an object is the ratio between its mass and its volume

The equation of the is d = \frac{m}{V} , where

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Let us use this equation to solve the question

∵ An object has a density of 1.3 g/cm³

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→ Substitute them in the equation of the denisty above

∵ 1.3 = \frac{m}{2}

→ Multiply both sides by 2

∴ 2 × 1.3 = 2 × \frac{m}{2}

∴ 2.6 = m

∴ The mass of the object is 2.6 grams

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