Garret grew 2 2/3 inches each year for the past 3 years. How many inches total has Garret grown in the past 3 years ?

Find the measure of each numbered angle for each figure

cricket20 [7]

Answer:

Angle 1 is 58. Angle 2 is 32.

Step-by-step explanation:

The measure of Angle ACB is 90 because C is on the circle and A and B connect to form a diameter of the circle. So, Angle 1 and Angle 2 add up to 90 (total degrees in triangle - 90). Now you can add the expressions the question gave for Angle 1 and Angle 2, and you get 7x + 6. So you have the equation 7x + 6 = 90. Solve the equation and you get x = 12. Now you can plug in that value for x into the expressions for Angles 1 and 2 to find their measures.

6 0

3 years ago

Please help! I really don't understand!

Varvara68 [4.7K]

A. yes this is a statistical question. it is a statistical question because you can answer the question by collecting data.

b. some clusters are.. 3,4,5, and 6 they are clusters because they are assembled around a particular value. the peak is 6 because it is the highest number it reaches. there are no gaps in this table.

c. to calculate the average with a graph you sum the numbers then divide by the total number of values in the set. for this table you add 1+2+3+3+4+4+4+5+5+5+5+5+5 then you divide by 15.

1+2+3+3+4+4+4+5+5+5+5+5+5=51

51 ÷ 15= 3.4

3 0

3 years ago

Figure EFGHK as shown below is to be transformed to figure E′F′G′H′K′ using the rule

MAVERICK [17]

9514 1404 393

Answer:

(a) (4, 8)

Step-by-step explanation:

Apply the transformation rule to the coordinates of point H.

(x, y) → (x +8, y +5)

H(-4, 3) → H'(-4 +8, 3 +5) = H'(4, 8)

4 0

3 years ago

In 1960, the population of a town was 14 thousand people. Over the course of the next 50 years, the town grew at a rate of 30 pe

andre [41]

SOLUTIONS

Given: Assume y is the population

$\begin{gathered} t=0=1960,y=14030 \\ t=1=1961,y=14060 \\ so\text{ b = 14000} \\ so\text{ k = 30} \end{gathered}$

The town grow at the rate of 30 people per year.

$y=kt+14000$ $y=30t+14000$

(A) The population predicted to be in 2030 will be

$\begin{gathered} 2030-1960=70 \\ y=30k+14000 \\ y=30(70)+14000 \\ y=2100+14000 \\ y=16100people \end{gathered}$

(B) so when y = 15000, find t

$\begin{gathered} y=15000 \\ y=30t+14000 \\ 15000=30t+14000 \\ 15000-14000=30t \\ 1000=30t \\ t=\frac{1000}{30} \\ t\approx33 \\ t=1960+33 \\ t=1993 \end{gathered}$

3 0

11 months ago

What is the area of a parallelogram whose bases are 9

Nady [450]

 Base=9cm

height=3 cm

Area of parallelogram=b*h

 =9*3

 =27cm^2.

Hope this will help u...:)

6 0

3 years ago