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morpeh [17]
3 years ago
8

Someone help math please due today

Mathematics
1 answer:
natali 33 [55]3 years ago
5 0

Answer:

What is the question

Step-by-step explanation:

So u can solve it for u

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The perimeter of a rectangle is 120 centimeters. The base is 3 times the height. What are the dimensions of the rectangle? a. h
baherus [9]

Answer:

Height = 15

Base = 45

Step-by-step explanation:

Given

Shape: Rectangle

Perimeter = 120cm

Base = 3 * Height

Required

Determine the dimensions

The perimeter of a rectangle is:

Perimeter = 2 * (Base + Height)

Substitute 120 for Perimeter

120 = 2 * (Base + Height)

Divide both sides by 2

60 = Base + Height

Substitute 3 * Height for Base

60 = 3 * Height + Height

60 = 3Height + Height

60 = 4Height

Divide both sides by 4

15 = Height

Height = 15

Substitute 15 for Height in Base = 3 * Height

Base = 3 * 15

Base = 45

6 0
3 years ago
PLZ PLZ PLZ CAN SOMEONE HELP WITH MATHS DISTANCE TIME GRAPHS!!!
Kisachek [45]

Answer:

Tbh I have no clue..

8 0
3 years ago
Which of the fractions are equivalent to 6/8 ? Select all that apply.
NARA [144]

Answer:

abcdef

Step-by-step explanation:

6 0
3 years ago
Please help me ASAP!!!!!!!!
Gekata [30.6K]

A sequence is arithmetic if the subtraction between any pair of consecutive terms is constant.


A sequence is arithmetic if the ratio between any pair of consecutive terms is constant.


Let's pick consecutive couples and check their difference and ratio:


First couple: first and second term

Difference: 0 - (-2) = 0+2 = 2

Ratio: \frac{0}{-2} = 0


Second couple second and third terms:

Difference: 2 - 0 = 2

Ratio: \frac{2}{0} = \text{undefined}


So, we can see that the difference remained constant (is always 2), while the ratio isn't even defined. So, this is an arithmetic sequence.


As a corollary, you can see that a geometric sequence can never contain 0. Otherwise, when checking consective ratios, that 0 will eventually be a denominator and break the procedure.

3 0
4 years ago
Given that (x-3)(Ax²+bx+c)=x³-7x-6,find the value of A,B and C​
faltersainse [42]

Answer:

Given that (x-3) (Ax²+bx+c) = x³-7x-6, find the value of A, B and C

      

Given that (x-3) (Ax²+bx+c) = x³-7x-6, find the value of A, B and C

4 0
3 years ago
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