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3 years ago

Pls help will give brainliest

Mathematics

1 answer:

jeka57 [31]3 years ago

8 0

A) (6,0)

Since the points of R are found after x = 0 and x = 2, and found before x = 8, the value for x cannot start with those numbers so it would have to be either 4 or 6.

The rhombus is a square but more like a diamond shape with all equal sides. So if the difference between Q & T is (2,4), then you would have to go backwards by the same amount from (8,4)

So mathematically speaking...

(8,4) - (2,4) = (6,0)

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Please help I will give brainiest

vovikov84 [41]

Answer:

Step-by-step explanation:

The constant of proportionality is what determines the relationship between y and x. If t is the constant of proportionality then an example is y = tx .

So 4 is the constant of proportionality

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3 years ago

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HELP ME!!!!!!!!!!!!!!!!!!!!111

Vlad1618 [11]

Answer:

-40

Step-by-step explanation:

(-40) divided by 5 is (-8)

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3 years ago

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Let $$X_1, X_2, ...X_n$$ be uniformly distributed on the interval 0 to a. Recall that the maximum likelihood estimator of a is $

Solnce55 [7]

Answer:

a) $\hat a = max(X_i)$

For this case the value for $\hat a$ is always smaller than the value of a, assuming $X_i \sim Unif[0,a]$ So then for this case it cannot be unbiased because an unbiased estimator satisfy this property:

$E(a) - a= 0$ and that's not our case.

b) $E(\hat a) - a= \frac{na}{n+1} - a = \frac{na -an -a}{n+1}= \frac{-a}{n+1}$

Since is a negative value we can conclude that underestimate the real value a.

$\lim_{ n \to\infty} -\frac{1}{n+1}= 0$

c) $P(Y \leq y) = P(max(X_i) \leq y) = P(X_1 \leq y, X_2 \leq y, ..., X_n\leq y)$

And assuming independence we have this:

$P(Y \leq y) = P(X_1 \leq y) P(X_2 \leq y) .... P(X_n \leq y) = [P(X_1 \leq y)]^n = (\frac{y}{a})^n$

$f_Y (Y) = n (\frac{y}{a})^{n-1} * \frac{1}{a}= \frac{n}{a^n} y^{n-1} , y \in [0,a]$

e) On this case we see that the estimator $\hat a_1$ is better than $\hat a_2$ and the reason why is because:

$V(\hat a_1) > V(\hat a_2)$

$\frac{a^2}{3n}> \frac{a^2}{n(n+2)}$

$n(n+2) = n^2 + 2n > n +2n = 3n$ and that's satisfied for n>1.

Step-by-step explanation:

Part a

For this case we are assuming $X_1, X_2 , ..., X_n \sim U(0,a)$

And we are are ssuming the following estimator:

$\hat a = max(X_i)$

$E(a) - a= 0$ and that's not our case.

Part b

For this case we assume that the estimator is given by:

$E(\hat a) = \frac{na}{n+1}$

And using the definition of bias we have this:

$E(\hat a) - a= \frac{na}{n+1} - a = \frac{na -an -a}{n+1}= \frac{-a}{n+1}$

Since is a negative value we can conclude that underestimate the real value a.

And when we take the limit when n tend to infinity we got that the bias tend to 0.

$\lim_{ n \to\infty} -\frac{1}{n+1}= 0$

Part c

For this case we the followng random variable $Y = max (X_i)$ and we can find the cumulative distribution function like this:

$P(Y \leq y) = P(max(X_i) \leq y) = P(X_1 \leq y, X_2 \leq y, ..., X_n\leq y)$

And assuming independence we have this:

$P(Y \leq y) = P(X_1 \leq y) P(X_2 \leq y) .... P(X_n \leq y) = [P(X_1 \leq y)]^n = (\frac{y}{a})^n$

Since all the random variables have the same distribution.

Now we can find the density function derivating the distribution function like this:

$f_Y (Y) = n (\frac{y}{a})^{n-1} * \frac{1}{a}= \frac{n}{a^n} y^{n-1} , y \in [0,a]$

Now we can find the expected value for the random variable Y and we got this:

$E(Y) = \int_{0}^a \frac{n}{a^n} y^n dy = \frac{n}{a^n} \frac{a^{n+1}}{n+1}= \frac{an}{n+1}$

And the bias is given by:

$E(Y)-a=\frac{an}{n+1} -a=\frac{an-an-a}{n+1}= -\frac{a}{n+1}$

And again since the bias is not 0 we have a biased estimator.

Part e

For this case we have two estimators with the following variances:

$V(\hat a_1) = \frac{a^2}{3n}$

$V(\hat a_2) = \frac{a^2}{n(n+2)}$

On this case we see that the estimator $\hat a_1$ is better than $\hat a_2$ and the reason why is because:

$V(\hat a_1) > V(\hat a_2)$

$\frac{a^2}{3n}> \frac{a^2}{n(n+2)}$

$n(n+2) = n^2 + 2n > n +2n = 3n$ and that's satisfied for n>1.

8 0

3 years ago

Select the order in which the flow of current is listed from greatest to least

noname [10]

Answer:Short circuit, closed circuit, open circuit

8 0

3 years ago

Lake Michigan's volume is approximately 1,180 cubic miles and its surface area is approximately 14,332,090 acres. The 2015 water

galben [10]

Answer:

a.) depth of the lake = (volume of the lake) / area of lake

= 173,693,585,360,000 / 624,305,840,400 = 278.22 feet

b.) 11 inches = 0.9167 feet

Water gained in cubic feet gained by the lake

= 624,305,840,400 $\times$ 0.9167

= 572,282,434,719.5 cubic feet

c.) the percentage change in the lake volume over that year

= 572,282,434,719.5 cubic feet / 173,693,585,360,000 cubic feet

= 0.0033

= 0.33%

Step-by-step explanation:

i) acres to square feet : 1 acre = 43560 square feet

therefore 14,332,090 acres = 624,305,840,400 square feet

ii) 1 mile = 5280 feet

1 cubic mile = 5280 $\times$ 5280 $\times$ 5280 = 147,197,952,000 cubic feet

therefore 1180 cubic miles = 173,693,585,360,000 cubic feet

a.) depth of the lake = (volume of the lake) / area of lake

= 173,693,585,360,000 / 624,305,840,400 = 278.22 feet

b.) 11 inches = 0.9167 feet

Water gained in cubic feet gained by the lake

= 624,305,840,400 $\times$ 0.9167 = 572,282,434,719.5 cubic feet

c.) the percentage change in the lake volume over that year

= 572,282,434,719.5 cubic feet / 173,693,585,360,000 cubic feet

= 0.0033

= 0.33%

7 0

4 years ago