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3 years ago

What is the IQR of 11,11.5,10.5,17,14.5,18,17,19

Mathematics

2 answers:

exis [7]3 years ago

8 0

Answer:

6.25

Step-by-step explanation:

10.5, 11, 11.5, 14.5, 17, 17, 18, 19

Median: 15.75

Lower quartile: 11.25

Upper quartile: 17.5

Interquartile range: 17.5 - 11.25 = 6.25

Vika [28.1K]3 years ago

4 0

Ascending order :-

10.5 , 11 , 11.5 , 14.5 , 17 , 17 , 18 , 19

Median,

={(n/2)th + (n/2 +1)th}/2

={(4)th + (5)th}/2

=(31.5)/2

=15.75

I.Q.R.,

Median of lower half,

={(n/2)th + (n/2 +1)th}/2

={(2)th + (3)th}/2

=(22.5)/2

= 11.25

Median of upper half,

={(n/2)th + (n/2 +1)th}/2

={(2)th + (3)th}/2

=35/2

=17.5

I.Q.R. = 17.5 - 11.25 = 6.25

HOPE THIS WILL HELP YOU

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6. Calculate the area of the octagon in the figure below.

Kryger [21]

Answer:

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Step-by-step explanation:

The octagon is irregular, meaning not all sides have equal length. However, we can break it up into other shapes to find the area.

The octagon shown in the figure is a composite figure as it's composed of other shapes. In the octagon, let's break it up into:

4 triangles (corners)
3 rectangles (one in the middle, two on top after you remove triangles)

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Area of rectangle with length $l$ and width $w$ : $A=lw$
Area of triangle with base $b$ and height $h$ : $A=\frac{1}{2}bh$

Area of triangles:

All four triangles we broke the octagon into are congruent. Each has a base of 2 and a height of 2.

Thus, the total area of one is $A=\frac{1}{2}\cdot 2\cdot 2=2\text{ square units}$

The area of all four is then $2\cdot 4=8$ units squared.

Area of rectangles:

The two smaller rectangles are also congruent. Each has a length of 3 and a width of 2. Therefore, each of them have an area of $3\cdot 2=6$ units squared, and the both of them have a total area of $6\cdot 2=12$ units squared.