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3 years ago

The difference between the set of non-negative real numbers and the set of positive real numbers is:

Mathematics

1 answer:

Inessa05 [86]3 years ago

4 0

Answer:

C; A singleton set

Step-by-step explanation:

Mathematically, when a number is non-negative; it is either positive or zero

Now, this is because 0 identifies as neither a positive or a negative number

hence, when we find the difference between the two sets, the only number that stands out unmatched is the value 0

What this mean is that we are having a set with a single number result

So we have our answer as {0}

Which is a singleton set

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#10) Cross multiply and divide to solve for x* 2/5 = X/70

Annette [7]

Answer:

28=x

Step-by-step explanation:

2/5=x/70

(70/1)(2/5)=x/70(70/1)

here you cancel 70 into 5 to get 14 and on the other side cancel both the 70s

14*2=x

28=x

4 0

3 years ago

Read 2 more answers

You work two jobs. You earn $14.64 per hour as a salesperson and $12.20 per hour stocking shelves. Your combined earnings this m

Igoryamba

I'm assuming you have to graph a line that shows the combination of earnings.

Our equation is 14.64y + 12.20x = 219.60

We'll be solving for x and y. We'll need to substitute the variables, one at a time, to 0, in order to find their intercepts.

Let's do x first.

14.64(0) + 12.20x = 219.60

12.20x = 219.60

Divide by 12.20 on both sides.

x = 18

Now let's solve for y.

14.46y + 12.20(0) = 219.60

14.46y = 219.60

Divide both sides by 14.46.

y = 15.18

That is actually a long decmal, but since we're dealing with money, we round it down to the nearest cent.

So, now we know x = 18 and y = 15.18.

Graph those on the x coordinate plane and the y coordinate plane, and make a line connecting the two. That line represents all the solutions.

7 0

3 years ago

Which expression is a sum of cubes?

erik [133]

we know that

A polynomial in the form $a^{3} +b^{3}$ is called a sum of cubes

Let's verify each case to determine the solution

case A) $-64x^{6} y^{12} +125x^{16} y^{3}$

we know that

$-64=-4^{3}$

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{16}=x^{15} *x=x*(x^{5})^{3}$ -------> is not a perfect cube

$y^{3}= (y)^{3}$

therefore

the case A) is not a sum of cubes

case B) $-32x^{6} y^{12} +125x^{16} y^{3}$

we know that

$-32=-2^{5}$ -------> is not a perfect cube

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{16}=x^{15} *x=x*(x^{5})^{3}$ -------> is not a perfect cube

$y^{3}= (y)^{3}$

therefore

the case B) is not a sum of cubes

case C) $32x^{6} y^{12} +125x^{9} y^{3}$

we know that

$32=2^{5}$ -------> is not a perfect cube

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{9}=(x^{3})^{3}$

$y^{3}= (y)^{3}$

therefore

the case C) is not a sum of cubes

case A) $64x^{6} y^{12} +125x^{9} y^{3}$

we know that

$64=4^{3}$

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{9}=(x^{3})^{3}$

$y^{3}= (y)^{3}$

Substitute

$4^{3}(x^{2})^{3}(y^{4})^{3} +5^{3}(x^{3})^{3}(y)^{3}$

$(4x^{2}y^{4})^{3} +(5x^{3}y)^{3}$

therefore

the answer is

$64x^{6} y^{12} +125x^{9} y^{3}$ is a sum of cubes

6 0

3 years ago

Read 2 more answers

What is the difference of the values of the two variables in this system of equations? y = 2x + 1 x + 3y = 10 A. 0 B. 1 C. 2 D.

Tema [17]

C. 2 is the difference of the values of the two variables in the system of equations hope this helps!

3 0

4 years ago

Can you please fill in this table?

ELEN [110]

Answer:

Middle School In Favor: 25%

Middle School Not in Favor: 75%

High School In Favor 20%

High School Not In Favor 80%

Step-by-step explanation:

For the middle school in favor, we need to find the percent, which is 50 out of 200, so its 1/4, 25%

So the rest of the middle school is not in favor, which is 75%

High school is 60 not in favor, so we need to find the percentage. So 60 out is 300 is 20%

And we just subtract 20 from 100 which leaves us with 80

3 0

2 years ago

Read 2 more answers