Remark
A kite is constructed such that AB = BC and AD = DC. AB = sqrt( (1/2)AC + 18^2) see diagram. AD = sqrt(24^2 + 32^2)
Step One
Solve for AB
1/2 AC = 24 (AC is given as 48)
18 is a given length
AB = sqrt(24^2 + 18^2) = sqrt(576 + 324) = sqrt(900) = 30
Step Two
Find the length of AD
AD = sqrt(32^2 + 24^2) = sqrt(1024 + 576) = sqrt(1600) = 40
Step Three
Find the Perimeter.
P = 2 * 30 + 2*40 = 60 + 80 = 140
P = 140 <<<<< Answer
Cut only to ends of the triangle off then it will have a pentagon with the uncut shape
I started the problem, hope this helps
Answer:
Step-by-step explanation:
6 + 5 + 7 + 1 + 0 = 19
Answer:
(a) 1
(b) 1
(c) 3.03
Step-by-step explanation:
The given quadratic equation is
Subtract 27 from both sides.
Taking out common factor.
Divide both sides by 4.
If an expression is , then we need to add , to make it perfect square.
Here, b=2, so
Add 1 on both sides.
Taking square root on both sides.
Subtract 1 from both sides.
and
and
Only one solution is positive.
Greatest solution is 3.031, therefore the approximate value of this solution is 3.03.
