add the two 6 ft together and that gives you 12 ft. then add 7 in + 6 in which gives you 13 in. There are 12 in a foot, so you take 12 away from the 13 giving you 1 in remaining and 1 additional foot to add to the 12.

6 0

3 years ago

Analyze the pre-image ABCD. What are the vertices of the final image if T–1, –2 ◦ ry = x is applied to figure ABCD?

mariarad [96]

Answers:

A''(3, 0); B''(3, 2); C''(1, 1); D''(1, -1)

Explanation:

We perform the reflection across y=x first. This reflection switches the x- and y-coordinates; this maps:

A(2, 4)→A'(4, 2)

B(4, 4)→B'(4, 4)

C(3, 2)→C'(2, 3)

D(1, 2)→D'(2, 1)

Next we perform the translation. This translation shifts the figure 1 unit left and 2 units down, by subtracting 1 from the x-coordinate and 2 from the y-coordinate. This maps:

A'(4, 2)→A''(3, 0)

B'(4, 4)→B''(3, 2)

C'(2, 3)→C''(1, 1)

D'(2, 1)→D''(1, -1)

6 0

3 years ago

Read 2 more answers

How do you write ten fifteens in the simplest form for fraction

kirza4 [7]

10/15 divided by 5 = 5/10

5 0

3 years ago

Read 2 more answers

Differentiate the function. f(x) = ln(25 sin^2(x))

tigry1 [53]

Use the chain rule.
Let u = 25sin²(x), such that dy/dx = dy/du · du/dx

$\frac{dy}{dx} = \frac{1}{25sin^{2}(x)} \cdot 50cos(x) \cdot sin(x)$
$\frac{dy}{dx} = \frac{2cos(x) sin(x)}{sin^{2}(x)}$

$\frac{dy}{dx} = 2cot(x)$

8 0

4 years ago