The ball will hit the ground when h(t)=0 so:
-16t^2+10t+100=0
Using the quadratic equation:
t=(-10±√6500)/-32, and since t>0
t≈2.8 seconds (to nearest tenth of a second)
Answer:
Less than
Step-by-step explanation:
Although it wasn't an option, it is less than. In order to accurately compare then, you have to get the least common denominator. Using the least common multiple (2), you multiply 5/8 by 2 and end up with 10/16. Now 10 is less than 11, so the option is neither of those. 5/8 is less than 11/16.
Answer:
3/4
Step-by-step explanation:
Answer <u>(assuming it is allowed to be in point-slope format)</u>:

Step-by-step explanation:
1) First, determine the slope. We know it has to be perpendicular to the given equation,
. That equation is already in slope-intercept form, or y = mx + b format, in which m represents the slope. Since
is in place of the m in the equation, that must be the slope of the given line.
Slopes that are perpendicular are opposite reciprocals of each other (they have different signs, and the denominators and numerators switch places). Thus, the slope of the new line must be
.
2) Now, use the point-slope formula,
to write the new equation with the given information. Substitute
,
, and
for real values.
The
represents the slope, so substitute
in its place. The
and
represent the x and y values of a point the line intersects. Since the point crosses (1,4), substitute 1 for
and 4 for
. This gives the following equation and answer:

Answer:
(2,6)
Step-by-step explanation:
<u><em>The options of the questions are</em></u>
(0,1) (1,3) (2,6) (3,27)
and the given function is 
we know that
If a ordered pair lie on the graph of the given equation, then the ordered pair must satisfy the given equation
<u><em>Verify each ordered pair</em></u>
case 1) (0,1)
substitute the value of x and the value of y in the linear equation and then compare the results

----> is true
so
The ordered pair lie on the graph of the given equation
case 2) (1,3)
substitute the value of x and the value of y in the linear equation and then compare the results

----> is true
so
The ordered pair lie on the graph of the given equation
case 3) (2,6)
substitute the value of x and the value of y in the linear equation and then compare the results

----> is not true
so
The ordered pair not lie on the graph of the given equation
case 4) (3,27)
substitute the value of x and the value of y in the linear equation and then compare the results

----> is true
so
The ordered pair lie on the graph of the given equation