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3 years ago

Why did populist party want to have a silver standard instead of a gold standard?

Mathematics

1 answer:

PtichkaEL [24]3 years ago

4 0

The Democratic party wanted to have a silver standard

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Answer #1,3,4,5,6,and 7

Fofino [41]

Can you type the answers in plz. I can't see the pic

7 0

3 years ago

In which number does the 5 represent a value of 10 times the value represented by 5 in 35,187

Dvinal [7]

Answer:

well, there are no multiple choice options, but the answer is whichever number has a 5 in the ten thousands place like 56,789

Step-by-step explanation:

6 0

3 years ago

Is y=x+9 linear or is it not linear

avanturin [10]

Answer: It is linear. When a line is linear it just means it makes a straight line when you graph it. When it isn’t it will be curved or in some weird shape.

Step-by-step explanation:

3 0

3 years ago

Using this formula l=A 1/2 what is the length of one side of a square with an area of 1,936 square kilometers? (A is the area of

Vera_Pavlovna [14]

c.)44 kilometers

Answer:

Solution given:

let

length =L

and

Area =A

Now

we have

Area [A]=1936 square kilometers

now

As we know that

Area of square :length *length

A=l*l

A=l²

Substituting value of A

1936=l²

doing square root on both side

$\sqrt{1936}=\sqrt{l²}$

we get

l= $\sqrt{2*2*2*2*11*11}$

l=2*2*11

l=44 kilometers

the length of one side of a square is 44 kilometers.

6 0

2 years ago

A veterinarian wants to know if pit bulls or golden retrievers have a higher incidence of tooth decay at the age of three. The v

BigorU [14]

Answer: B) [-0.0332,0.1332]

Step-by-step explanation: Confidence Interval is an interval where we can be a percentage sure the true mean is.

The confidence interval for a difference in population proportion is calculated following these steps:

First, let's find population proportion for each population:

$p_{1}=\frac{30}{120}=0.25$

$p_{2}=\frac{32}{160}=0.2$

Second, calculate standard deviation for each proportion:

$\sigma_{1}=\sqrt{\frac{0.25(0.75)}{120} } = 0.0395$

$\sigma_{2}=\sqrt{\frac{0.2(0.8)}{160} } = 0.0316$

Now, we calculate standard error for difference:

$SE=\sqrt{\sigma_{1}^{2}+\sigma_{2}^{2}}$

$SE=\sqrt{0.0395^{2}+0.0316^{2}}$

SE = 0.0505

The z-score for a 90% CI is 1.645.

Then, confidence interval is

$p_{1}-p_{2}$ ± z-score.SE

$0.25-0.2$ ± $1.645(0.0505)$

0.05 ± 0.0831

The limits of this interval are:

inferior: 0.05 - 0.0831 = $-0.0332$

superior: 0.05 + 0.0831 = 0.1332

The 90% confidence interval for the difference in the population proportion of pit pulls and golden retrievers is $[-0.0332,0.1332]$ .

8 0

3 years ago