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erastova [34]
3 years ago
11

If the Quadratic functions for the equations are graphed, which is the widest?

Mathematics
1 answer:
Amanda [17]3 years ago
7 0

y = ax^2

If the absolute value of a is <1 the graph is wider than when a = 1

If the absolute value of a is >1 the graph is narrow than when a = 1

The only function that fits that description is  

y = 2x^2

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Please help me out :)
arlik [135]

Answer:

\frac{\sqrt{17} }{7}

Step-by-step explanation:

Using the Pythagorean identity

sin²x + cos²x = 1, then

sinx = \sqrt{1-cos^2x}

Note that (\frac{4\sqrt{2} }{7})² = \frac{32}{49}

sinΘ = \sqrt{1-(32/49)}

        = \sqrt{\frac{17}{49} } = \frac{\sqrt{17} }{7}

5 0
3 years ago
Select two ratios that are equivalent to <br> what are ratios are equivalent to 2:9
finlep [7]

Answer:

3,18    4,27

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A data mining routine has been applied to a transaction dataset and has classified 88 records as fraudulent (30 correctly so) an
Firlakuza [10]

Answer:

The classification matrix is attached below

Part a

The classification error rate for the records those are truly fraudulent is 65.91%.

Part b

The classification error rate for records that are truly non-fraudulent is 96.64%

Step-by-step explanation:

The classification matrix is obtained as shown below:

The transaction dataset has 30 fraudulent correctly classified records out of 88 records, that is, 30 records are correctly predicted given that an instance is negative.

Also, there would be 88 - 30 = 58 non-fraudulent incorrectly classified records, that is, 58 records are incorrectly predicted given that an instance is positive.

The transaction dataset has 920 non-fraudulent correctly classified records out of 952 records, that is, 920 records are correctly predicted given that an instance is positive.

Also, there would be 952 - 920 = 32 fraudulent incorrectly classified records, that is, 32 records incorrectly predicted given that an instance is negative.

That is,

                                                                            Predicted value

                           Active value                 Fraudulent       Non-fraudulent

                              Fraudlent                         30                       58

                          non-fraudulent                   32                     920

The classification matrix is obtained by using the information related to the transaction data, which is classified into fraudulent records and non-fraudulent records.

The error rate is obtained as shown below:

The error rate is obtained by taking the ratio of \left( {b + c} \right)(b+c) and the total number of records.

The classification matrix is, shown above

The total number of records is, 30 + 58 + 32 + 920 = 1,040

The error rate is,

\begin{array}{c}\\{\rm{Error}}\,{\rm{rate}} = \frac{{b + c}}{{{\rm{Total}}}}\\\\ = \frac{{58 + 32}}{{1,040}}\\\\ = \frac{{90}}{{1,040}}\\\\ = 0.0865\\\end{array}  

The percentage is 0.0865 \times 100 = 8.65

(a)

The classification error rate for the records those are truly fraudulent is obtained by taking the rate ratio of b and \left( {a + b} \right)(a+b) .

The classification error rate for the records those are truly fraudulent is obtained as shown below:

The classification matrix is, shown above and in the attachment

The error rate for truly fraudulent is,

\begin{array}{c}\\FP = \frac{b}{{a + b}}\\\\ = \frac{{58}}{{30 + 58}}\\\\ = \frac{{58}}{{88}}\\\\ = 0.6591\\\end{array}  

The percentage is, 0.6591 \times 100 = 65.91

(b)

The classification error rate for records that are truly non-fraudulent is obtained by taking the ratio of d and \left( {c + d} \right)(c+d) .

The classification error rate for records that are truly non-fraudulent is obtained as shown below:

The classification matrix is, shown in the attachment

The error rate for truly non-fraudulent is,

\begin{array}{c}\\TP = \frac{d}{{c + d}}\\\\ = \frac{{920}}{{32 + 920}}\\\\ = \frac{{920}}{{952}}\\\\ = 0.9664\\\end{array}

The percentage is, 0.9664 \times 100 = 96.64

6 0
3 years ago
A carton has a length of fraction 2 and 1 over 6 feet, width of fraction 1 and 1 over 5 feet, and height of fraction 2 and 1 ove
ozzi

Answer:

6 1/2 cubic feet

Step-by-step explanation:

A carton has a length of 2 1/6 feet

The width is 1 1/5 feet

The height is 2 1/2 feet

Therefore the volume of the carton can be calculated as follows

= length × width × height

= 2 1/6 × 1 1/5 × 2 1/2

= 13/6 × 6/5 × 5/2

= 390/60

= 13/2

= 6 1/2 cubic feet

Hence the volume of the carton is 6 1/2 cubic feet

3 0
3 years ago
Gina wants to take dance classes. She compares two dance studios to determine which has the best deal for her. Dance World charg
fomenos

Answer:

10 classes

Step-by-step explanation:

Given equations in the question

Dance World: y = 15x

Toe Tappers: y = 25 + 12.5x

Where,

x = number of classes

Equate the total cost at both dance studios

15x = 25 + 12.5x

Collect like terms

15x - 12.5x = 25

2.5x = 25

Divide both sides by 2.5

2.5x / 2.5 = 25 / 2.5

x = 10 classes

x = number of classes = 10

4 0
3 years ago
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