Question

If an angle is 10 degree less than its complement, find the angle.​

Answer 1

Let one be x

• Other one is x-10

ATQ

$\\ \sf \longmapsto x+x-10=90$

$\\ \sf \longmapsto 2x-10=90$

$\\ \sf \longmapsto 2x=90+10$

$\\ \sf \longmapsto 2x=100$

$\\ \sf \longmapsto x=\dfrac{100}{2}$

$\\ \sf \longmapsto x=50$

$\\ \sf \longmapsto x-10=50-10=40$