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Ede4ka [16]
3 years ago
7

Solve Using the Quadratic Formula x2+2x - 40 = -8 -2x​

Mathematics
1 answer:
ycow [4]3 years ago
4 0

Answer:

x = 4, x= -8

Step-by-step explanation:

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if the measure of <BEC is (2x+3)° and x=30, which expression could represent the measure of <AED?​
Maurinko [17]

Answer:

The answer is 3x-27

Step-by-step explanation:

If the angles are vertical from each other it means they are congruent. 2x+30 is 63, you plug in the x, 2(30)+30. You do that to the second one and also get 63, 3(30)-27. Therefore 3x-21 is the answer.

8 0
3 years ago
What is 3/8 divided by 4/5
olasank [31]
So,

To divide a fraction by a fraction, all you need to do is invert the second fraction and multiply the resulting fractions.

Step 1: Flip the second fraction.
\frac{3}{8} / \frac{5}{4}

Step 2: Multiply the fractions.
\frac{15}{32}\ or\ 0.46875\ or\ 46.875\ percent
6 0
3 years ago
Can anyone please help me with this?
kotykmax [81]

y^4+12y^2+36=(y^2)^2+12y^2+36\\\\\text{substitute}\ y^2=t\\\\t^2+12t+36=t^2+2\cdot t\cdot6+6^2\leftarrow\text{It's a perfect square}\\\\\text{use}\ (a+b)^2=a^2+2ab+b^2\\\\=(t+6)^2=(t+6)(t+6)\\\\\text{we're going back to substitution}\\\\=(y^2+6)(y^2+6)\\\\(\sqrt6)^2=6\to(i\sqrt6)^2=-6\\\\\text{therefore}\\\\=(y^2-(i\sqrt6)^2)(y^2-(i\sqrt6)^2)\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\boxed{(y-i\sqrt6)(y+i\sqrt6)(y-i\sqrt6)(y+i\sqrt6)}

6 0
4 years ago
WILL GIVE BRAINIEST FOR WHO ANSWERS IT CORRECTLY!! Create a list of steps, in order, that will solve the following equation. 1/2
Colt1911 [192]

Answer: subtract 2 and then multiply 2 then spuare root both sides then subtract  5

Step-by-step explanation:hope this helps god bless

5 0
3 years ago
What is the lateral surface area of this right pyramid with a square base?
Brums [2.3K]

Answer:

The lateral surface area of a square pyramid is the sum of the areas of the side faces only, whereas the surface area is the lateral area + area of the base. The lateral area of a square pyramid = 2al (or) 2a√[(a 2 /4) + h 2]. To get the surface area, we need to add the area of the base (which is a 2) to each of these formulas.The surface area of a square pyramid = a 2 + 2al (or) a 2 + 2a[(a 2 /4) + h 2]. where, a = Length of the base (square) l = slant height; h = height of the pyramid.

Step-by-step explanation:

hope this helps if not let me know have a great day :)

7 0
2 years ago
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