All categories

3 years ago

How do I solve two-step equations ex. 3g+5=17

2 answers:

8 0

Easy ! you first subtract the 5 to itself and to the 17, so 5 - 5 and 17 - 5. your equation should look like 3g = 12. since we need to isolate the variable (g) we need to divide 3 by itself and 12 by 3, so 3 ÷ 3 and 12 ÷ 3. now you have g = 4!

andreyandreev [35.5K]3 years ago

6 0

3g+5=17
-5 -5 your subtracting the number
3g = 12
12 divided by 3 = 4

You might be interested in

If the base of a triangle is doubled then new area= ________ times old area

Masteriza [31]

Answer:

As base and height are becoming double the new area is 4 times the original area. When the length of the sides of a triangle double, the area becomes quadruple.

3 0

3 years ago

2x+6y=12 what's m and b?

Elena L [17]

If you're asking about slope and how to find the equation of the line, you would do it like this:

1) Arrange the equation into slope intercept form (y=mx+b)

2) 6y+2x=12 subtract the 2x from both sides and you get 6y= -2x +12

is in slope intercept form

3) So, m= -2 and b=12

5 0

3 years ago

Read 2 more answers

Can someone tell me why this isn’t a function? I thought it was because each input has an output.

aksik [14]

Answer: I think it's because you can't have two of the same numbers in the domain. For example the (5, -3) and the (5,2)

Step-by-step explanation:

6 0

3 years ago

Lucy ate ½ of the cake. Blake ate¼of the cake.How much more cake did Lucy eat than Blake?

kirill115 [55]

1/4 more of the cake

7 0

3 years ago

Two number cubes are rolled sequentially. What is the probability that the first number cube shows a five and the other number c

nexus9112 [7]

The probability of first number cube shows a five and the other number cube shows an even number is $\frac{1}{12}$ .

Solution:

Two cubes are rolled sequentially.

Sample space when two dies are rolled

$=\left\{\begin{array}{l}{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)} \\{(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)} \\{(3,1), 3(, 2),(3,3),(3,4),(3,5),(3,6)} \\{(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)} \\{(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)} \\{(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}\end{array}\right\}$

Number of sample space = 36

Even numbers getting when two cubes rolled are 2, 4, 6.

First number cube shows a five and the other number cube shows an even number = {(5, 2), (5, 4), (5 6)}

Number of first number cube shows a five and the other number cube shows an even number = 3

Probability of first number cube shows a five and the other number cube shows an even number

$=\frac{\text{Number of outcomes}}{\text{Total number of sample space}}$

$$=\frac{3}{36}$

$$=\frac{1}{12}$

Hence, the probability of first number cube shows a five and the other number cube shows an even number is $\frac{1}{12}$ .

8 0

3 years ago