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3 years ago

How do I solve two-step equations ex. 3g+5=17

2 answers:

8 0

Easy ! you first subtract the 5 to itself and to the 17, so 5 - 5 and 17 - 5. your equation should look like 3g = 12. since we need to isolate the variable (g) we need to divide 3 by itself and 12 by 3, so 3 ÷ 3 and 12 ÷ 3. now you have g = 4!

andreyandreev [35.5K]3 years ago

6 0

3g+5=17
-5 -5 your subtracting the number
3g = 12
12 divided by 3 = 4

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The length of each side of an equilateral triangle is increased by 20%, resulting in triangle ABC. If the length of each side of

kompoz [17]

Answer: Area of ΔABC is 2.25x the area of ΔDEF.

Step-by-step explanation: Because equilateral triangle has 3 equal sides, area is calculated as

$A=\frac{\sqrt{3} }{4} a^{2}$

with a as side of the triangle.

Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:

a₁ = 1.2a

Then, its area is

$A_{1}=\frac{\sqrt{3} }{4}(1.2a)^{2}$

$A_{1}=\frac{\sqrt{3} }{4}1.44a^{2}$

Triangle DEF is 20% smaller than the original, which means its side is:

a₂ = 0.8a

So, area is

$A_{2}=\frac{\sqrt{3} }{4} (0.8a)^{2}$

$A_{2}=\frac{\sqrt{3} }{4} 0.64a^{2}$

Now, comparing areas:

$\frac{A_{1}}{A_{2}}= (\frac{\sqrt{3}.1.44a^{2} }{4})(\frac{4}{\sqrt{3}.0.64a^{2} } )$

$\frac{A_{1}}{A_{2}} =$ 2.25

The area of ΔABC is 2.25x greater than the area of ΔDEF.

7 0

3 years ago

Which of the following statements must be true about the polynomial function f(x)? If 1+ the sqrt of 13 is a root of f(x), then

son4ous [18]

The correct answer is: if $1 + 13i$ is a root of $f(x)$ , then $1 - 13i$ is also a root of $f(x)$ .

In fact, every polynomial has real and/or complex solutions. If all solutions are real, we're good. But if not all of them are real, then the complex ones come in couple of conjugate solutions. Since $1 + 13i$ and $1 - 13i$ are conjugate complex numbers, if one of them is a solution, the other must be as well.

7 0

3 years ago

Read 2 more answers

An online ticket seller charges $44 for each ticket to a concert, plus a fixed handling fee of $12. Define the unknown variables

const2013 [10]

The unknown variables are how many tickets are being bought and the total.

t=tickets

x=total

44t+12=x

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4 years ago

At the school cafeteria, each student who ordered lunch gets 6 chicken nuggets. The cafeteria staff prepares enough for 300 kids

lesya [120]

1800.... 300 students x 6 nuggets per student= 1800 total :)

4 0

3 years ago

Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega

AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$