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Grace [21]
3 years ago
5

An ISA specifies a word size of 8 bytes, byte addressability, and an address space of 256 K; it uses single-word instructions (i

.e. each instruction is a single 8 byte word). What is the size of the MAR
Computers and Technology
1 answer:
VladimirAG [237]3 years ago
6 0

Answer:

2 bytes

Explanation:

Size of the MAR ( memory address register )  = 18 bits = 2 bytes

Given that

address space = 256 K  = 2^8

number of address location= 2^8  * 2^10       ( where 1K = 2^10 )  

                                              = 2^18

Given the number of address location = 2^18 ;

Hence  18 bits are required to store the address of the instruction

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Write a program that reads in a temperature value in °F. Create a function ConvertFahrenheit that takes that value as a paramete
larisa86 [58]

Answer:

#include<stdio.h>

void ConvertFahrenheit(float);

void main()

{

float fahrenheit_temp;

printf("Input the temperature in Fahrenheit: ");

 

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}

void ConvertFahrenheit(float fahren) {

float c, k;

 

c = (fahren - 32)/1.8;

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printf("Celsius = %f\n", c);

printf("Kelvin = %f", k);

}

Explanation:

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