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Grace [21]
3 years ago
5

An ISA specifies a word size of 8 bytes, byte addressability, and an address space of 256 K; it uses single-word instructions (i

.e. each instruction is a single 8 byte word). What is the size of the MAR
Computers and Technology
1 answer:
VladimirAG [237]3 years ago
6 0

Answer:

2 bytes

Explanation:

Size of the MAR ( memory address register )  = 18 bits = 2 bytes

Given that

address space = 256 K  = 2^8

number of address location= 2^8  * 2^10       ( where 1K = 2^10 )  

                                              = 2^18

Given the number of address location = 2^18 ;

Hence  18 bits are required to store the address of the instruction

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4 years ago
Write a program that reads the number of stalls and then prints out diagrams in the format given above when the stalls become fi
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/* package whatever; // don't place package name! */

import java.util.*;

import java.lang.*;

import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */

public class Ideone

{

  public static final int STALL_COUNT = 10;

 

public static int find_stall(boolean[] stalls) {

int longest_count = -1;

int longest_length = 0;

int current_count = -1;

int current_length = 0;

boolean inRun = false;

for (int i = 0; i < stalls.length; i++) {

if (inRun && stalls[i]) {

inRun = false;

if (current_length >= longest_length) {

longest_length = current_length;

longest_count = current_count;

}

 

}

else if (!inRun && !stalls[i]) {

inRun = true;

current_count = i;

current_length = 1;

}

else if (inRun && !stalls[i]) {

current_length += 1;

}

}

if (inRun) {

if (current_length >= longest_length) {

longest_length = current_length;

longest_count = current_count;

}

}

return (longest_length - 1) / 2 + longest_count;

}

 

public static void print_pattern(boolean[] stalls) {

for (int i = 0; i < stalls.length; i++) {

if (stalls[i]) {

System.out.print("X ");

}

else {

System.out.print("_ ");

}

}

System.out.println();

}

 

  public static void main (String[] args) throws java.lang.Exception

  {

      boolean[] stalls = new boolean[STALL_COUNT];

for (int i = 0; i < stalls.length; i++) {

stalls[find_stall(stalls)] = true;

print_pattern(stalls);

  }

}

}

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