Answer:
<em>The registers that are compared are instructions 3 and 4</em>
<em>Explanation:</em>
<em>From the question given,</em>
<em>Recall that we need to explain what the hazard detection unit is doing during the 5th cycle of execution and which registers are being compared.</em>
<em>Now,</em>
<em>The instructions on the 5th cycle, at the stage ID/EX and IF/ID:</em>
<em>The instruction values are in ID/EX : sub $t2, $t3, $t6 (instruction 3)</em>
<em>The instruction values are in IF/ID: sub $t3, $t1 $t5 (instruction 4)</em>
<em>The register $t3 is compared in the instructions 3 and 4</em>
<em>The hazard detection unit between instruction 4 and 5t o be compared, it need to find out the values of $t1</em>
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There are two ways to convert from hexadecimal to denary gcse method. They are:
- Conversion from hex to denary via binary.
- The use of base 16 place-value columns.
<h3>How is the conversion done?</h3>
In Conversion from hex to denary via binary:
One has to Separate the hex digits to be able to know or find its equivalent in binary, and then the person will then put them back together.
Example - Find out the denary value of hex value 2D.
It will be:
2 = 0010
D = 1101
Put them them together and then you will have:
00101101
Which is known to be:
0 *128 + 0 * 64 + 1 *32 + 0 * 16 + 1 *8 + 1 *4 + 0 *2 + 1 *1
= 45 in denary form.
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"Key logger" This could be software or hardware that does this.
Answer:
In order to reduce the risk of accidents on the roads.
Explanation:
The special equipment is used when testing eyesight for a driver's license in order to reduce the risk of accidents on the roads. Good eyesight is very important for good and safe driving so to find out the eyesight of the driver, the license officer used special equipment in order to check driver's eyes. If the eyesight is good, the officer provide license to the person otherwise not so that no accidents happen on the road.
It is true that in the array implementation of a queue, the pop operation is most efficient if the front of the queue is fixed at index position. The correct option is a.
<h3>What is pop operation? </h3>
The removal of an element is referred to as a pop operation. Again, because we only have access to the element at the top of the stack, we can only remove one element. We simply take the top of the stack off.
A push operation decrements the pointer before copying data to the stack; a pop operation copies data from the stack before incrementing the pointer.
The pop operation in an array implementation of a queue is most efficient if the queue's front is fixed at index position.
Thus, the correct option is a.
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