Answer:
def wordsOfFreqency(words, freq):
text1 = "Apple apPLE mangO aPple orange Orange apple guava Mango mango"
words = []
words1 = []
words1 = text1.split()
words = [x.upper() for x in words1]
freq=[words.count(w) for w in words]
print(dict(zip(freq,words)))
return words
def main():
wordsOfFreqency(words, freq)
if __name__=="__main__":
main() # call main function
Explanation:
This will print the list of strings as per its word frequency.
Output is :
{4: 'APPLE', 3: 'MANGO', 2: 'ORANGE', 1: 'GUAVA'}
Answer:
Controls, families, domain
Explanation:
ISSCC means international information systems security certification consortium.
They are also known as ISC square, they offer two security certification the cissp and sccp.
Answer:
c.
Explanation:
Based on the information provided within the question it can be said that the best option in this scenario would be to implement an endpoint management server appliance. This is a software or dedicated appliance that is used in order to discover, manage, and control any and all computer devices that are trying to access the corporate network. This allows you to remove individuals as well as administrative rights from those trying to connect or that are already connected.
Answer:
Passwords must meet basic complexity requirements.
Explanation:
Password should contain:
- special characters like @#$%^&*
Passwords should not contain:
- user's name or surname
- birth year/date
- not similar to previous password
- account/identity number
