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Nata [24]
3 years ago
6

Which expression is equivalent to RootIndex 4 StartRoot StartFraction 16 x Superscript 11 Baseline y Superscript 8 Baseline Over

81 x Superscript 7 Baseline y Superscript 6 Baseline EndFraction EndRoot? Assume x Greater-than 0 and y not-equals 0. StartFraction 4 x (RootIndex 4 StartRoot y squared EndRoot) Over 9 EndFraction StartFraction 2 x (RootIndex 4 StartRoot y squared EndRoot) Over 3 EndFraction StartFraction 4 x squared y Over 9 EndFraction StartFraction 2 x squared y Over 3 EndFraction
Mathematics
2 answers:
trasher [3.6K]3 years ago
5 0

Answer:

I said D

Step-by-step explanation:

storchak [24]3 years ago
5 0

Answer:

its d i just took the test

Step-by-step explanation:

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True or false? Help please
Leokris [45]

Answer:

but I don't know,I hope you understand

Step-by-step explanation:

i hope you understand ☺️

if who one knows please answer her/his question

thank you

7 0
3 years ago
Describe and correct the error a student made in identifying the common difference of the following sequence.
Sonja [21]

Given:

The sequence is 29, 22,​ 15, 8,​ 1, ...

To find:

The common difference.

Solution:

We have,

29, 22,​ 15, 8,​ 1, ...

It is an AP.

First term : a_1=29

Second term : a_2=22

Now,

Common difference : d=a_2-a_1

d=22-29

d=-7

Therefore, the correct common difference is -7.

Note: Here calculation by student is not given, so we cannot find the error of the student.

7 0
3 years ago
What is the answer to <br>x^2+2y^2=33<br>x+y=3
9966 [12]
X^2=-2y^2+33
x= \sqrt{-2y^2} or x=- \sqrt{-2y^2+33}
5 0
3 years ago
Read 2 more answers
Pls help me! Thanks a lot
Juliette [100K]

Answer:

Please Give BRAINLIEST!

Step-by-step explanation:

Quadrant 4, from x - axis go right 2 units

Quadrant 4 from x - axis go down 3 units.

7 0
2 years ago
Read 2 more answers
leonard is flying kite he is holding the end of the string at distance of 1.2 m above the ground. if the string is 15 m how long
larisa86 [58]

Answer:

The kite is 10.8 m above the ground.

Step-by-step explanation:

Here we can make a triangle rectangle like the one shown in the graph below, where we want to find the value of the cathetus X, and that plus 1.2m will be the distance between the kite and the ground.

Notice that X is the opposite cathetus to the 40° angle, then:

We can use the relation:

Sin(θ) = (opposite cathetus)/(hypotenuse)

where, in our case, we have:

θ = 40°

hypotenuse = 15m

opposite cathetus = X

Replacing these in the equation, we get:

Sin(40°) = X/15m

Now we can solve this for X.

Sin(40°)*15m = X = 9.6m

And the actual height of the kite is X + 1.2m

Then:

H = 9.6m + 1.2m = 10.8m

The kite is 10.8 m above the ground.

7 0
3 years ago
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