Answer:
148
Explanation:
According to Hardy-Weinberg equilibrium,
p + q = 1
p² + 2pq + q² = 1 where,
p = frequency of dominant allele
q = frequency of recessive allele
p² = frequency of homozygous dominant genotype
2pq = frequency of heterozygous genotype
q² = frequency of homozygous recessive genotype
Here,
Total population = 592
Number of NN people = 148
Frequency of N blood group or NN genotype (q²) = 148/592 = 0.25
q = √0.25 = 0.5
p = 1 - q
= 1 - 0.5 = 0.5
Hence, p = 0.5
Frequency of MM genotype = p² = 0.25
Number of people with MM genotype = 0.25*592 = 148
Hence, 148 people will have MM genotype or M blood group.
Answer:
The correct answer is - 0.084
Explanation:
Sickle cell anemia is a autsmal recessive blood disorder of RBCs where RBC shape altered to the sickle shape or cresecent moon that obstruct and damage the veins and artries.
Normal allele is represented by - HbA - p
sickel cell allele is represented by - HbS - q
genotype frequency of normal allele HbA in the population = p2
genptype frequency of HbAHbS in the population = 2pq
genotype frequency of autosomal recessive HbS = q2 = 0.007 (given)
So, the allelic frequency of the recessive allele =
q = √ 0.007 = 0.08366 or 0.084
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