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2 years ago

Find the value of x -Geometry in Two and Three Dimensions -will give brainliest-

Mathematics

1 answer:

scoray [572]2 years ago

7 0

Answer:

B. i think

Step-by-step explanation:

You might be interested in

28 ⅓ minutes to run 3 ⅓ miles

shtirl [24]

Answer:

(I'm assuming you find how many miles in a minute.) 0.013 miles.

Step-by-step explanation:

So in order to find the amount of miles in a minute you are going to divide it.

10/3 divided by 85/3 = 0.013 miles in a minute.

3 0

2 years ago

Hi pls help answer this!

Morgarella [4.7K]

Answer:

363-138=-5x

Step-by-step explanation:

Let c = cost

We know that the total cost is $363:

363-??????

We also know that he spent $138 on parts:

363-138?????

And we are solving for the cost of labor per hour:

363-138=5x

We can use this equation to find the total cost of labor per hour.

Hence, your equation will be 363-138=5x

7 0

1 year ago

F(x) = 3/(x + 2) - sqrt(x - 3) complete the following statement: f(19)=

liberstina [14]

Answer:

f(19)=3/21-4=-3.857

Step-by-step explanation:

f(x)=3/(x+2)-sqrt(x-3)

f(19)=3/(19+2)-sqrt(19-3)

f(19)=3/21-sqrt(16)

f(19)=3/21-4

f(19)=-3.857

5 0

3 years ago

URGENT HELP ME PLEASE

Trava [24]

Answer:

(a) $\log_3(\dfrac{81}{3})=3$

(b) $\log_5(\dfrac{625}{25})=2$

(d) $\log_4(\dfrac{64}{16})=1$

(e) $\log_6(36^4)=8$

(f) $\log(100^3)=6$

Step-by-step explanation:

Let as consider the given equations are $\log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?$ .

(a)

$\log_3(\dfrac{81}{3})=\log_3(27)$

$\log_3(\dfrac{81}{3})=\log_3(3^3)$

$\log_3(\dfrac{81}{3})=3$ $[\because \log_aa^x=x]$

(b)

$\log_5(\dfrac{625}{25})=\log_5(25)$

$\log_5(\dfrac{625}{25})=\log_5(5^2)$

$\log_5(\dfrac{625}{25})=2$ $[\because \log_aa^x=x]$

(c)

$\log_2(\dfrac{64}{8})=\log_2(8)$

$\log_2(\dfrac{64}{8})=\log_2(2^3)$

$\log_2(\dfrac{64}{8})=3$ $[\because \log_aa^x=x]$

(d)

$\log_4(\dfrac{64}{16})=\log_4(4)$

$\log_4(\dfrac{64}{16})=1$ $[\because \log_aa^x=x]$

(e)

$\log_6(36^4)=\log_6((6^2)^4)$

$\log_6(36^4)=\log_6(6^8)$

$\log_6(36^4)=8$ $[\because \log_aa^x=x]$

(f)

$\log(100^3)=\log((10^2)^3)$

$\log(100^3)=\log(10^6)$

$\log(100^3)=6$ $[\because \log10^x=x]$

5 0

3 years ago

Find the perimeter of a rectangle with sides (3x-5) and (-2x+10)

Vinil7 [7]

2(3x-5) + 2(-2x+10)
6x-10 + -4x+ 20

=2x+ 10

5 0

3 years ago