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elena-s [515]
2 years ago
11

Find the value of x -Geometry in Two and Three Dimensions -will give brainliest-

Mathematics
1 answer:
scoray [572]2 years ago
7 0

Answer:

B. i think

Step-by-step explanation:

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28 ⅓ minutes to run 3 ⅓ miles
shtirl [24]

Answer:

(I'm assuming you find how many miles in a minute.) 0.013 miles.

Step-by-step explanation:

So in order to find the amount of miles in a minute you are going to divide it.

10/3 divided by 85/3 = 0.013 miles in a minute.

3 0
2 years ago
Hi pls help answer this!
Morgarella [4.7K]

Answer:

363-138=-5x

Step-by-step explanation:

Let c = cost

We know that the total cost is $363:

363-??????

We also know that he spent $138 on parts:

363-138?????

And we are solving for the cost of labor per hour:

363-138=5x

We can use this equation to find the total cost of labor per hour.

Hence, your equation will be 363-138=5x

7 0
1 year ago
F(x) = 3/(x + 2) - sqrt(x - 3) complete the following statement: f(19)=
liberstina [14]

Answer:

f(19)=3/21-4=-3.857

Step-by-step explanation:

f(x)=3/(x+2)-sqrt(x-3)

f(19)=3/(19+2)-sqrt(19-3)

f(19)=3/21-sqrt(16)

f(19)=3/21-4

f(19)=-3.857

5 0
3 years ago
URGENT HELP ME PLEASE
Trava [24]

Answer:

(a)\log_3(\dfrac{81}{3})=3

(b)\log_5(\dfrac{625}{25})=2

(c)\log_2(\dfrac{64}{8})=3

(d)\log_4(\dfrac{64}{16})=1

(e)\log_6(36^4)=8

(f)\log(100^3)=6

Step-by-step explanation:

Let as consider the given equations are \log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?.

(a)

\log_3(\dfrac{81}{3})=\log_3(27)

\log_3(\dfrac{81}{3})=\log_3(3^3)

\log_3(\dfrac{81}{3})=3        [\because \log_aa^x=x]

(b)

\log_5(\dfrac{625}{25})=\log_5(25)

\log_5(\dfrac{625}{25})=\log_5(5^2)

\log_5(\dfrac{625}{25})=2        [\because \log_aa^x=x]

(c)

\log_2(\dfrac{64}{8})=\log_2(8)

\log_2(\dfrac{64}{8})=\log_2(2^3)

\log_2(\dfrac{64}{8})=3        [\because \log_aa^x=x]

(d)

\log_4(\dfrac{64}{16})=\log_4(4)

\log_4(\dfrac{64}{16})=1        [\because \log_aa^x=x]

(e)

\log_6(36^4)=\log_6((6^2)^4)

\log_6(36^4)=\log_6(6^8)

\log_6(36^4)=8            [\because \log_aa^x=x]

(f)

\log(100^3)=\log((10^2)^3)

\log(100^3)=\log(10^6)

\log(100^3)=6            [\because \log10^x=x]

5 0
3 years ago
Find the perimeter of a rectangle with sides (3x-5) and (-2x+10)
Vinil7 [7]
2(3x-5) + 2(-2x+10)
6x-10 + -4x+ 20

=2x+ 10
5 0
3 years ago
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