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arlik [135]
4 years ago
9

Applying Math 8. Solve the equation to show how I = v/r becomes R= v/l Show your work

Mathematics
1 answer:
Sergeu [11.5K]4 years ago
4 0

Answer:

Original  

l = v/r

first multiply each side by r to get it out of the denominator

rl = v

now divide by l to get r by itself

r = l/v

Step-by-step explanation:

Original  

l = v/r

first multiply each side by r to get it out of the denominator

rl = v

now divide by l to get r by itself

r = l/v

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Helpppp plzzz<br> Thank you
kaheart [24]

Answer:

a) GCF = 8

Step-by-step explanation:

b)

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3 years ago
The 20% tip on a $8 sandwich ​
melamori03 [73]

Answer:

Tip of $1.60

The total is $9.60

Step-by-step explanation:

(20% × $8) + $8

$1.60 + $8

$9.60

5 0
3 years ago
Help math question derivative!
atroni [7]
Let f(x)=\sec^{-1}x. Then \sec f(x)=x, and differentiating both sides with respect to x gives

(\sec f(x))'=\sec f(x)\tan f(x)\,f'(x)=1
f'(x)=\dfrac1{\sec f(x)\tan f(x)}

Now, when x=\sqrt2, you get

(\sec^{-1})'(\sqrt2)=f'(\sqrt2)=\dfrac1{\sec\left(\sec^{-1}\sqrt2\right)\tan\left(\sec^{-1}\sqrt2\right)}

You have \sec^{-1}\sqrt2=\dfrac\pi4, so \sec\left(\sec^{-1}\sqrt2\right)=\sqrt2 and \tan\left(\sec^{-1}\sqrt2\right)=1. So (\sec^{-1})'(\sqrt2)=\dfrac1{\sqrt2\times1}=\dfrac1{\sqrt2}
5 0
4 years ago
A sector with a radius of 8 cm has an area of 56pi cm2. What is the central angle measure of the sector in radians?
Maurinko [17]

Answer:

\frac{7\pi}{4}.

Step-by-step explanation:

Given information:

Radius of circle = 8 cm

Area of sector = 56\pi\text{ cm}^2

Formula for area of sector is

A=\dfrac{1}{2}\theta r^2

where, r is radius and \theta is central angle in radian.

Substitute A=56\pi and r=8 in the above formula.

56\pi=\dfrac{1}{2}\theta (8)^2

56\pi=\dfrac{64}{2}\theta

56\pi=32\theta

\dfrac{56\pi}{32}=\theta

\dfrac{7\pi}{4}=\theta

Therefore, the measure of the sector in radians is \frac{7\pi}{4}.

6 0
3 years ago
Find the Volume of this Octagonal Pyramid.<br> "B" represents the Area of the octagon base.
Dominik [7]

Answer:

7.06 x 10^(-7) ft 3

Step-by-step explanation:

We have the formula to calculate the volume of an octagonal Pyraamid as following:

<em>+) Volume of octagonal pyramid = 1/3 * Area of the base * Height</em>

As given, the base of the pyramid is an octagon with area equal to 15mm2

=> Area of the base = 15 mm2

The height of the pyramid is the length of the line segment which is perpendicular to the base - which is the red line.

=> Height = 4mm

So we have:

<em>Volume of octagonal pyramid = 1/3 * Area of the base * Height</em>

<em>= 1/3 * 15 * 4 = 20 mm3</em>

<em />

As: 1 mm3 = 3.53 x 10^(-8) ft 3

=> 20 mm3 = 7.06x10^(-7) ft 3

So the volume of the pyramid is :  7.06 x 10^(-7) ft 3

6 0
3 years ago
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