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3 years ago

Applying Math 8. Solve the equation to show how I = v/r becomes R= v/l Show your work

Mathematics

1 answer:

Sergeu [11.5K]3 years ago

4 0

Answer:

Original

l = v/r

first multiply each side by r to get it out of the denominator

rl = v

now divide by l to get r by itself

r = l/v

Step-by-step explanation:

Original

l = v/r

first multiply each side by r to get it out of the denominator

rl = v

now divide by l to get r by itself

r = l/v

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3 years ago

Is X-13=x+1 true or false

Black_prince [1.1K]

Answer: FALSE.

Step-by-step explanation:

Given the following equation provided in the exercise:

$x-13=x+1$

You need to solve for the variable "x".

In order to solve for "x" you can folllow the steps shown below:

1. You must apply the Addition property of equality and add 13 to both sides of the equation. Then:

$x-13+(13)=x+1+(13)\\\\x=x+14$

2. Finally you need to apply the Subtraction property of equality and subtract "x" from both sides of the equation. So you get:

$x-(x)=x+14-(x)\\\\0=14\ (FALSE)$

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3 years ago

What is 6.84 in word form

alexandr402 [8]

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(Note, you don't say, "Six point eighty-four" As it doesn't sound correct.

Cheers.

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3 years ago

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Dovator [93]

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3 years ago

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C. Gage bought a new car for $29,000 to use while he is away at college. The car depreciates (decreases in value) by 11% annuall

OverLord2011 [107]

Answer:

a. The value of the car will be $18,195.25

b. (i) 2.5 hours

(ii) 25 problems each

Step-by-step explanation:

a. To calculate the value of the car after four years, what we shall use is the exponential formula below;

F = PV( 1 - r)^t

where F is the value at year 4

PV is the present price = $29,000

r is the rate = 11% = 11/100 = 0.11

t is the time = 4 years

Substituting these values, we have;

F = 29,000(1-0.11)^4 = 29000(0.89)^4 = $18,195.25

The value of the car when he graduates will be $18,195

b. Let the number of hours it will take for both to have written the same number if problems

be x

For Ms B, the number of problems she would have written at that time will be 10 + 6(x)

For Ms D , the number of problems will be 10 * x = 10x

To get the time it will take for both to write same number of problems, we will need to equate the number of problems they would have written by hour x

Hence;

10 + 6x = 10x

10x-6x = 10

4x = 10

x = 10/4 = 2.5 hours

The number of problems would be;

For Ms B = 6(2.5) + 10 = 15 + 10 = 25

For Ms D = 10(2.5) = 25

They both would have written 25 problems at that time

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3 years ago