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Studentka2010 [4]

3 years ago

6

on a map highmount is 5 inches from pine hill if the map scale is 1 inch = 3 miles what is the actual distance between the towns

1 answer:

Anastasy [175]3 years ago

6 0

If 1 inch = 3 miles on the map, then 5 inches would = 15 miles (5 x 3 = 15)

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The coordinates of the endpoints of AB are A(-4, 3 ) and B ( 1, -3 ). Which measurment is closet to the length AB in units.

k0ka [10]

<u><em>Note: Since you may have probably unintentionally forgotten to add the choices, but I am solving this question as it would still help you clearing your concept and determining the correct choice. </em></u>

Answer:

The measurement is closet to the length AB will be $\sqrt{61}=7.81$ units

Step-by-step explanation:

As the coordinates of the endpoints of AB are

A(-4, 3 )
B( 1, -3 )

As we know that the distance between two points is basically termed as the length of the line segment AB connecting them

As

$\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

So,

$\mathrm{The\:distance\:between\:}\left(-4,\:3\right)\mathrm{\:and\:}\left(1,\:-3\right)\mathrm{\:is\:}$

$=\sqrt{\left(1-\left(-4\right)\right)^2+\left(-3-3\right)^2}$

$\mathrm{Apply\:rule}\:-\left(-a\right)=a$

$=\sqrt{\left(1+4\right)^2+\left(-3-3\right)^2}$

$=\sqrt{5^2+6^2}$

$=\sqrt{25+36}$

$=\sqrt{61}$

$=7.81$ units

So, the length AB or the distance between two points A(-4, 3 ) and

B ( 1, -3 ) will be $\sqrt{61}=7.81$ units

Therefore, the measurement is closet to the length AB will be $\sqrt{61}=7.81$ units

Keywords: distance between two points, distance formula

Learn more about distance between two points from brainly.com/question/9231324

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