In order to find height from where ball is dropped, you have to find height or h(t) when time or t is zero.So plug in t=0 into your quadratic equation:h(0) = -16.1(0^2) + 150h(0) = 0 +150h(0) = 150 ft is the height from where ball is dropped. When ball hits the ground, the height is zero. So plug in h(t) = 0 and solve for t.0 = -16.1t^2 + 15016.1 t^2 = 150t^2 = 150/16.1t = sqrt(150/16.1)t = ± 3.05Since time cannot be negative, your answer is positive solution i.e. t = 3.05
Answer:
97.8%
Step-by-step explanation:
110 is 2 standard deviations above the mean (6+6 = 12)
12+98 = 110
Looking at the standard deviation curve
P(x< or = to 110) = 1 - P(x>110)
We can find the probability that x>100 by adding anything above 2 standard deviations above the curve.
P(x>110) = 2.1+.1 = 2.2%
P(x< or = to 110) = 1 - P(x>110)
= 1- 2.2%
= 1- .022
= .978
= 97.8 %
Answer:
a. k = 8
b. k = 95
c. k = 13.95
d. k = 40
Step-by-step explanation:
Answer:
f(x) = 52
Step-by-step explanation:
f(x) does the same things as y, so when you get your answer, think of it as the value for y when x = - 4
The second thing you should know is that wherever you see an x on the right, you put in - 4
Let x = - 4
y = 2x^2 - 3x + 8
y = 2(-4)^2 - 3(-4) + 8
y = 2*16 - (-12) + 8
y = 32 + 12 + 8
y = 52
Be careful how you hand - 3x when -4 is put in for x. -3(-4) = 12 not - 12
f(-4) = 52
