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Nadusha1986 [10]
3 years ago
7

The discriminant of a quadratic equation is 225. Describe the nature of the roots.

Mathematics
1 answer:
Keith_Richards [23]3 years ago
5 0

Answer:

c

Step-by-step explanation:

d=225=15²>0

roots are real , rational and different.

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the student needed to place a ten outside the radical, as a perfect square of 100 composes 200. This way, a two should be left under the radical sign. Also, this would be about 14.1 because 14^2 is 196 and 15^2 is 225. The correct answer must be less than 225, more than 196, but closer to 196. Therefore, a .1 is added to the 14

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The product of (4z^2 + 7z - 8) and (-z + 3) is -4z^3 + xz^2 + yz - 24. What is the value of x? What is the value of y?
ycow [4]

Answer:

x=5+\frac{29}{z}-\frac{y}{z}

y=5z+29-xz

Step-by-step explanation:

Given: (4z^2+7z-8)(-z+3)=-4z^3+xz^2+yz-24; find x and y.

Let's start with finding x first. Let's distribute the left side of the equation.

-4z^3+5z^2+29z-24=-4z^3+xz^2+yz-24

Let's move everything we can to the left side of the equation. Some things will cancel out.

5z^2+29z=xz^2+yz

Now, let's move the term that includes x to the left side of the equation. Everything else should be moved to the right.

-xz^2=-5z^2-29z+yz

Let's get rid of the negative sign in front of x by dividing both sides by -1.

xz^2=5z^2+29z-yz

To get x completely isolated, divide both sides by z^2.

\frac{xz^2}{z^2}=\frac{5z^2}{z^2}+\frac{29z}{z^2}-\frac{yz}{z^2}

Simplify.

x=5+\frac{29}{z}-\frac{y}{z}

Let's solve for y. We will start with the distributed and simplified equation to make it easier.

5z^2+29z=xz^2+yz

Now, let's move the term that includes y to the left side of the equation. Everything else should be moved to the right.

-yz=-5z^2-29z+xz^2

Again, let's get rid of the negative sign in front of the y by dividing both sides by -1.

yz=5z^2+29z-xz^2

To isolate y, divide both sides by z.

\frac{yz}{z}=\frac{5z^2}{z}+\frac{29z}{z}-\frac{xz^2}{z}

Simplify.

y=5z+29-xz

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