The answer to this is quite simple my friend.
So if you were 9, purely turning on November 9th of 2015 at a undisclosed time, you would've been born in November of 2006. Currently, now of October 16, 2021, you would be:
Add:
4 + 10 + 1 = 15
So you would be 15 years old.
Hope this helps, currently it's 10/17/2021 for me and 1:56 am (EST).
Have a nice morning, night, dusk etc.
-ROR
Answer:
(This is a example since you don’t have anything to round to)
Example Answer if the radius is 4 - 50.24
Step-by-step explanation:
Example Radius : 4
Area : 3.14
We have the mulitiply 3.14 times The Example Radius 2 times because The diameter of a circle is 2 times its radius.
( 3.14 x 4 x 4) 50.24
If you know the diameter, it’s a half or 1/2 as large.
Therefore, if the radius was 4, it would be 50.24.
Youre welcome :)
Answer:
Step-by-step explanation:
The amount of money that Jason earns is dependent on the amount of time, t in hours that he works
The function f(x) = 15t represents the money he earns for working t hours. Therefore, the dependent variable is f(x) and the independent variable is t
Jason works at least 5 hours but not more than 10. This means that The minimum amount that he can earn is 15×5 = $75
The maximum amount that he can earn is 15×10 = $150
The practical domain is all possible values for t. It becomes
5 lesser than or equal to t lesser than or equal to 10
The practical range is all possible values for f(x). It becomes
75 lesser than or equal to f(x) lesser than or equal to 150
Answer:
3456
Step-by-step explanation:
24x12=288
288x12=3456
Given :
A function , x = 2cos t -3sin t .....equation 1.
A differential equation , x'' + x = 0 .....equation 2.
To Find :
Whether the given function is a solution to the given differential equation.
Solution :
First derivative of x :
Now , second derivative :
( Note : derivative of sin t is cos t and cos t is -sin t )
Putting value of x'' and x in equation 2 , we get :
=(-2cos t + 3sin t ) + ( 2cos t -3sin t )
= 0
So , x'' and x satisfy equation 2.
Therefore , x function is a solution of given differential equation .
Hence , this is the required solution .
