$\bf \qquad \qquad \textit{ratio relations} \\\\ \begin{array}{ccccllll} &\stackrel{ratio~of~the}{Sides}&\stackrel{ratio~of~the}{Areas}&\stackrel{ratio~of~the}{Volumes}\\ &-----&-----&-----\\ \cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array}\\\\ \rule{31em}{0.25pt}\\\\ \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}$

$\bf \rule{31em}{0.25pt}\\\\ \cfrac{smaller}{larger}\qquad \cfrac{s}{s}=\cfrac{\sqrt{98}}{\sqrt{162}}~~ \begin{cases} 98=2\cdot 7\cdot 7\\ \qquad 2\cdot 7^2\\ 162=2\cdot 9\cdot 9\\ \qquad 2\cdot 9^2 \end{cases}\implies \cfrac{s}{s}=\cfrac{\sqrt{2\cdot 7^2}}{\sqrt{2\cdot 9^2}} \\[2em] \cfrac{s}{s}=\cfrac{7\sqrt{2}}{9\sqrt{2}}\implies \cfrac{s}{s}=\cfrac{7}{9}$

bearing in mind that the ratio of the sides, is the same as the ratio of the perimeters.

6 0

3 years ago

Pls help ASAPI don’t understand can you show steps too pls

tensa zangetsu [6.8K]

Answer:

x = -2 , y = -1

(-2,-1)

4 0

3 years ago

in a class there are 40 students. There are 10 more boys than girls in the class, Let x be the number of boys and y be the numbe

belka [17]

X = boys
y = girls

x + y = 40 (in a class there are 40 students)
x = y + 10 (there are 10 more boys than girls in the class)

5 0

4 years ago

What would it be??????

igor_vitrenko [27]

-15 + (7-3) =

-15 + 4 =

-11

6 0

4 years ago