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Lostsunrise [7]
3 years ago
5

243^-y=(1/243)^3y*9^-2y a.) y=-1 b.) y=0 c.) y=1 d.) no solution

Mathematics
2 answers:
allochka39001 [22]3 years ago
8 0
243^{-y}=(\frac{1}{243})^{3y}\times 9^{-2y} has y = 0 as a solution.

Selection B is appropriate.
blondinia [14]3 years ago
7 0

Answer:

b.) y=0

Step-by-step explanation:

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Factor this expression.<br> x2 + 9x + 8
Ket [755]

Answer:

(x+1)(x+8) When factoring squares whose squared coefficient is one the roots must add up to the coefficient of the slope and multiply out to the intercept value.

6 0
3 years ago
Given the following geometric sequence, find the common ratio: {3, 18, 108, ...).
vodomira [7]
Geometric sequences go up due to a common ratio. Here the common ratio can be worked out by dividing a term by its previous term e.g term 2 divided by term 1.

18/3 = 6&#10;

Therefore the common ratio is 6.
4 0
3 years ago
4/5 plus what equals 1/2
VARVARA [1.3K]

Answer:  -3/10

Step-by-step explanation: A positive and a negative will subtract.

1. Find the common denominator (8/10)

2. simce 8/10 is greater than 1/2 you need to add a negative to get 8/10 a lower value

3. subtract 5/10 or 1/2 from 8/10 to figure out what gives you the correct answer

4 0
4 years ago
Read 2 more answers
PLZ HELP ASAP CONGRUENCE GEOMETRY
RoseWind [281]
The answer is 80 degrees. As you can see, the triangle is an isosceles triangle and both sides of the triangle equal 14. If both of the sides are congruent then the opposite angles are also congruent as well. Which means the 50 degrees in the left angle is congruent to the right angle, 50. Since triangles add up to 180 degrees, the answer for x would be 80. 

Hope this helped :)
4 0
3 years ago
The sum of an arithmeit cprogression consisting of 20 positive integer terms with positive common difference is equal to 2020. (
Rufina [12.5K]

Answer:

a) possible progressions are 5

b) the smallest and largest possible values of the first term are 16 and 82

Step-by-step explanation:

<u>Sum of terms:</u>

  • Sₙ = n/2(a₁ + aₙ) = n/2(2a₁ + (n-1)d)
  • S₂₀ = 20/2(2a₁ + 19d) = 10(2a₁ + 19d)
  • 2020 = 10(2a₁ + 19d)
  • 202 = 2a₁ + 19d

<u>In order a₁ to be an integer, d must be even number, so d = 2k</u>

  • 202 = 2a₁ + 38k
  • 101 = a₁ + 19k

<u>Possible values of k= 1,2,3,4,5</u>

  • k = 1 ⇒ a₁ = 101 - 19 = 82
  • k = 2 ⇒ a₁ = 101 - 38 = 63
  • k = 3 ⇒ a₁ = 101 - 57 = 44
  • k = 4 ⇒ a₁ = 101 - 76 = 25
  • k = 5 ⇒ a₁ = 101 - 95 = 16

<u>As per above, </u>

  • a) possible progressions are 5
  • b) the smallest and largest possible values of the first term are 16 and 82
6 0
3 years ago
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