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erastova [34]
3 years ago
14

Ed has $100 more than Robert. After Ed spends $20 on

SAT
2 answers:
Leviafan [203]3 years ago
5 0
I was gonna say do 100-80=20
20/5=16 so 16 is the answer
Serga [27]3 years ago
4 0
Ed has x+100

(x+100)-20=5x

x+100-20=5x

x+80=5x subtract x from each side

x-x+80=5x-x

80=4x divide each side by 4

x=20 (amount that Robert has)

x+100=20+100=120 dollars (amount that Ed has)

120-20=5*20

100=100
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Answer:

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7 0
3 years ago
The population of two different villages are modeled by the equations shown below. The population (in thousands) is represented
PilotLPTM [1.2K]

Answer:

1990 and 2010

y_l_w(15)=315\hspace{3}thousands\\y_l_c(15)=315\hspace{3}thousands\\y_l_w(35)=715\hspace{3}thousands\\y_l_c(35)=715\hspace{3}thousands

Explanation:

Let:

y_l_w=Population\hspace{3}of\hspace{3}Lewiston\\y_l_c=Population\hspace{3}of\hspace{3}Lockport

We need to know, in what year(s) the villages had the same population, mathematically this is:

y_l_w=y_l_c

So:

x^2-30x+540=20x+15\\\\Subtract\hspace{3}20x\hspace{3}from\hspace{3}both\hspace{3}sides\\\\x^2-50x+540=15\\\\Subtract\hspace{3}15\hspace{3}from\hspace{3}both\hspace{3}sides\\\\x^2-50x+525=0

Solving for x:

Factoring

(x-15)(x-35)=0

Hence:

x=15\\\\or\\\\x=35

Therefore the year(s) which the village had the same population are:

1975+15=1990\\\\and\\\\1975+35=2010

In order to find the population of both cities during the year(s) of equal population, just evalue the equations at x=15 and x=35:

y_l_w(15)=315\hspace{3}thousands\\y_l_c(15)=315\hspace{3}thousands\\y_l_w(35)=715\hspace{3}thousands\\y_l_c(35)=715\hspace{3}thousands

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Explanation:

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