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inn [45]
3 years ago
13

Please Help If m∠DBC = 10x and m∠ACB = 4x2- 6, find m∠ ACB.

SAT
1 answer:
zavuch27 [327]3 years ago
5 0
10x plus 4x(2-6) 
10x plus 8x - 24x 
8x-24x = -16x
-16x + 10x
-6x
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Into how many categories has the usda divided recipes
____ [38]

Answer:

it was divided into 9 categories

Explanation:

hope this helps;)

3 0
2 years ago
Tech a says that analog signals are continuously variable signals. Tech b says that digital signals are direct on/off signals wi
Blababa [14]

The person that is correct based on the two statements made by Tech A and Tech B is;

Both of them.

An analog signal is one that is continuous in both instances of time and amplitude.

Now, in the real world examples of Analog signals are; current, voltage, temperature, pressure, light intensity etc.

Meanwhile, the digital signals are those that contain the digital values which are usually converted at specific instances from the analog signal.

This means that they can have only 2 states which is On or Off.

Read more about analogue and digital signals at; brainly.com/question/15084481

7 0
2 years ago
T/F
azamat

The given statement "dual innervation is the term used to describe an organ that receives both sympathetic and parasympathetic motor impulses" is TRUE.

<h3>What is dual innervation?</h3>

Dual innervation refers to an organ's ability to receive both sympathetic and parasympathetic motor impulses. Sympathetic responses are extensive throughout the body, which is partially explained by the fact that a single sympathetic preganglionic fiber may synapse with 20 or more postganglionic fibers.

Examples of organs with dual innervation include the heart and the eye.

The parasympathetic system slows heart rate whereas the sympathetic system speeds it up.

While the parasympathetic system causes the pupil of the eye to constrict, the sympathetic system causes the pupil to enlarge.

The heart and lungs have separate innervations.

The vagus nerve's impact on the pacemaker cells of the heart has a tiny probability of affecting the rate and force of heart muscle contraction.

Therefore, the given statement "dual innervation is the term used to describe an organ that receives both sympathetic and parasympathetic motor impulses" is TRUE.

Know more about dual innervation here:

brainly.com/question/29665163

#SPJ4

6 0
1 year ago
Heyyyyyyyyy wydddddd
balandron [24]

Answer:

Obsessing over my friend who likes my other friend 0-0

Explanation:

5 0
2 years ago
Read 2 more answers
Calculate the time, in milliseconds, that it would take for 99 percent of the original cyclobutane at 1270k to decompose.
crimeas [40]

Answer:

(i) The order of decomposition reaction of cyclobutane is first order.

(ii) It requires 53.15 milliseconds for 99% decomposition of cyclobutane.

(d) Rate law = k [\rm Cl_2Cl

2

, as chlorine is the reactant.

(e) Thus student claim is false as Chlorine gas is the reactant, not a catalyst.

(i) The order of reaction can be determined with the help of a graph given below. The graph depicts the reduction in the concentration of cyclobutane with time depicting decomposition.

The graph depicts the reaction to be of first-order kinetics. The general concentration expression can be:

\rm C_(_t_)\;=\;C_(_0_)\;e^-^k^t

Where, \rm C_(_t_) = concentration at time t

\rm C_(_0_) = initial concentration 1.60 mol/liter

k = rate constant

for first order reaction,

k = In \rm \frac{2}{Half\;time}

Halftime

2

From the graph, half time  = 0.008 sec i.e. time when the concentration reduced to 50%.

k = In \rm \frac{2}{0.008}

0.008

2

 

k = 86.64 / sec.

(ii) The time required for 99% decomposition can be calculated, by calculating the \rm C_(_t_) for left 1 % solution.

0.01 \rm C_(_0_)  =  \rm e^-^k^t

-kt = -4.605

t = 53.15 miliseconds

(d) The rate law is obtained against the reaction.

In rate law, the intermediates that appear in the reaction are removed, and the equation has been formed.  

The slow step is the formation of Chlorine. Thus the rate law will be:

Rate = k [\rm Cl_2Cl

2

(e) The catalyst function in improvising the rate of the reaction. Since, the reaction has chlorine as the part of the reactant, it is consumed in the reaction and thus does not act as a catalyst. Thus the claim of the student is false.

7 0
2 years ago
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