Answer:
18
Step-by-step explanation:
90-80=10
10*2=20
20-2=18
Answer:
<em><u>2</u></em><em><u>.</u></em><em><u>3</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>(</u></em><em><u> </u></em><em><u>3</u></em><em><u>,</u></em><em><u> </u></em><em><u>1</u></em><em><u>)</u></em><em><u> </u></em>
Step-by-step explanation:
1) Simplify 3 × (1, 1) 3 × (1, 1) to 3× 1, 13 × 1,1.
<em>2</em><em>.</em><em>3</em><em> </em><em>-</em><em> </em><em>(</em><em> </em><em>3</em><em> </em><em>×</em><em> </em><em>1</em><em>,</em><em> </em><em>1</em><em> </em><em>)</em>
2) Simplify 3 × 1 to 3.
2.3 - ( 3, 1)
<em><u>Therefor</u></em><em><u>,</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>2</u></em><em><u>.</u></em><em><u>3</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>(</u></em><em><u> </u></em><em><u>3</u></em><em><u>,</u></em><em><u> </u></em><em><u>1</u></em><em><u>)</u></em><em><u>.</u></em>
Answer:
Step-by-step explanation:
Both 115 and 145 mph are above the mean. Draw a normal curve and mark these speeds. 115 mph is 1 standard deviation above the mean; 130 would be 2 standard deviations above the mean; and 145 would be 3 s. d. above it.
We need to find the area under the standard normal curve between 115 and 145. This is equivalent to the area under the standard normal curve between z = 1 and z = 3.
I used my TI-83 Plus calculator's DISTR function "normalcdf(" to calculate this area: normalcdf(1, 3) = 0.1573.
The area between z = 1 and z = 3 is 0.1573. In other words, the percentage of serves that were between 115 and 145 mph was 15.73%.
C is 23 because if you get all rhe numbers and measure thats your answer. I think i might be wrong. if I am then sorry
Answer:
12 is the answer
Step-by-step explanation:
