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LekaFEV [45]
3 years ago
5

PLS HELP ME, YOULL SAVE ME

Mathematics
1 answer:
Olin [163]3 years ago
5 0

Answer:

Third option:

Step-by-step explanation:

<u>Graph of functions</u>

The graph shown in the image corresponds to a curved line passing through points (0,2) and (4,4).

Option 1:

y=\sqrt{x+2}

Substituting x=0:

y=\sqrt{0+2}=\sqrt{2}

The point is not (0,2), thus the function is incorrect.

Option 2:

y=x+2

This function corresponds to a straight line with slope 1 and y-intercept 2.

The graph is a curved line, thus the function is incorrect.

Option 3:

y=\sqrt{x}+2

Substituting x=0:

y=\sqrt{0}+2

y=0+2=2

Now test the point x=4:

y=\sqrt{4}+2

y=2+2=4

The point (4,4) also corresponds to the function on the graph. This proof is not conclusive, but since the other options do not match, this is the correct option.

Option 4:

y=\sqrt{x}-2

Substituting x=0:

y=\sqrt{0}-2

y=-2

The point should be (0,2) and not (0,-2). Incorrect function

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The given logarithmic expression is

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We rewrite \frac{1}{16} in the index form to base 4.

This implies that;

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