Answer:
Step-by-step explanation:
we can simply find the relative frequency as foloows:
We are given are No piercings, One or two piercings, and More than two piercings. The relative frequency with no piercings is 188/361 = 0.521, the relative frequency for one or two piercings is 82/361 = 0.227. The total has to add to 361, so there are 361−188−82 = 91 students with more than two piercings, and the relative frequency is 91/361 = 0.252. the below table describes each.
