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ale4655 [162]
3 years ago
14

Marie can find the volume of a cube by using the formula V = 53, where s represents the side length of the cube. If Marie's

Mathematics
1 answer:
dimulka [17.4K]3 years ago
6 0

Answer:

The volume of her cube is 15.625cm^3

Step-by-step explanation:

The formula V = s³, where s represents the side length of the cube.

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The normal water level in the river is 0. Now it is 2 feet below normal.
Mademuasel [1]

The question can't be answered with the information given.

First of all, we don't know how fast the rain is falling ... how many inches
per hour.

But even of we knew that, that would only tell us how much water would
pile up in our yard or on our street.  You're talking about a river, and
that's a whole different ball game. 

The rain that falls right here is going to flow down the river to somewhere
else.  But the rain that falls up-river from us is going to flow down to where
we are, and the river is going to rise.  The amount it rises depends on . . .

-- how fast the rain is falling,
-- how much area it's falling on,
-- how much forest there is in that area and how many houses and
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6 0
3 years ago
Read 2 more answers
34.75 divided by 5 equals what
Hoochie [10]

Answer:

6.95

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Can someone help me?
soldier1979 [14.2K]

Answer:

Step-by-step explanation:

First your going to plug in what p and q are into the equation so 3(2)^5+10(-3)^2 over 7(2)+1.

Your going to first do (2)^5 and (-3)^2 so it’s going to be 3(32)+10(9) over (multiply the 7(2) first) 14+1.

3(32)+10(9) over 14+1 now multiply 3(32) and 10(9) you should get (96)+(90) over 15.

add 96+90 to get 186 over 15.

then divide how many times 15 can go into 186 you should get 12 6/15 and divide 6/15 by 3 to get your final answer 12 2/5.

I hope this helps!

5 0
3 years ago
You believe the population is normally distributed. Find the 80% confidence interval. Enter your answer as an open-interval (i.e
victus00 [196]

You intend to estimate a population mean μ from the following sample. 26.2 27.7 8.6 3.8 11.6 You believe the population is normally distributed. Find the 80% confidence interval.  Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places.

Answer:

The  Confidence interval = (8.98 , 22.18)

Step-by-step explanation:

From the given information:

mean = \dfrac{ 26.2+ 27.7+ 8.6+ 3.8 +11.6 }{5}

mean = 15.58

the standard deviation \sigma = \sqrt{\dfrac{\sum(x_i - \mu)^2 }{n}}

the standard deviation = \sqrt{\dfrac{(26.2  - 15.58)^2 +(27.7 - 15.58)^2 +(8.6  - 15.58)^2 + (3.8  - 15.58)^2  + (11.6  - 15.58)^2  }{5 }  }

standard deviation = 9.62297

Degrees of freedom df = n-1

Degrees of freedom df = 5 - 1

Degrees of freedom df = 4

For df  at 4 and 80% confidence level, the critical value t from t table  = 1.533

The Margin of Error M.O.E = t \times \dfrac{\sigma}{\sqrt{n}}

The Margin of Error M.O.E = 1.533 \times \dfrac{9.62297}{\sqrt{5}}

The Margin of Error M.O.E = 1.533 \times 4.3035

The Margin of Error M.O.E = 6.60

The  Confidence interval = ( \mu  \pm M.O.E )

The  Confidence interval = ( \mu  +  M.O.E , \mu - M.O.E )

The  Confidence interval = ( 15.58 - 6.60 , 15.58 + 6.60)

The  Confidence interval = (8.98 , 22.18)

7 0
3 years ago
Simplify: (2x²y²) (-3xy³)<br>please no links and explain please. I need it fast​
Shtirlitz [24]

Step-by-step explanation:

Solution:

(6xy) × (-3x²y³)

= {6 × (-3)} × {xy × x²y³}

= -18x1+2 y1+3

= -18x³y⁴.

3 0
3 years ago
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