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den301095 [7]
3 years ago
8

On a piece of paper, Graph y

Mathematics
2 answers:
creativ13 [48]3 years ago
5 0
The answer to this question is A
saveliy_v [14]3 years ago
3 0
The answer for it is A
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Suppose that the Celsius temperature at the point (x, y) in the xy-plane is T(x, y) = x sin 2y and that distance in the xy-plane
liraira [26]

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

P = (\frac{1}{2}, \frac{\sqrt 3}{2})

Answer:

Rate = 0.935042^\circ /cm

Step-by-step explanation:

Given

P = (\frac{1}{2}, \frac{\sqrt 3}{2})

T(x,y) =x\sin2y

r = 1m

v = 2m/s

Express the given point P as a unit tangent vector:

P = (\frac{1}{2}, \frac{\sqrt 3}{2})

u = \frac{\sqrt 3}{2}i - \frac{1}{2}j

Next, find the gradient of P and T using: \triangle T = \nabla T * u

Where

\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})}  = (sin \sqrt 3)i + (cos \sqrt 3)j

So: the gradient becomes:

\triangle T = \nabla T * u

\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] *  [\frac{\sqrt 3}{2}i - \frac{1}{2}j]

By vector multiplication, we have:

\triangle T = (sin \sqrt 3)*  \frac{\sqrt 3}{2} - (cos \sqrt 3)  \frac{1}{2}

\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)

\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5

\triangle T = 0.935042

Hence, the rate is:

Rate = \triangle T = 0.935042^\circ /cm

3 0
2 years ago
What is 20+20909909090909090909090909090909090
Katena32 [7]
20,909,909,090,000,000,000,000,000,000,000,000
6 0
2 years ago
Is the sequence -3, 1, 5, 9,... An arithmetic sequence
kramer

Answer:

Yes, it's an arithmetic sequence.

Step-by-step explanation:

Each term in this sequence is 4 more than the previous term.  Therefore we have an arithmetic sequence.

6 0
3 years ago
The temperature one morning in Shasta was LaTeX: -12^\circ F− 12 ∘ F. By the afternoon, the temperature had risen LaTeX: 8^\circ
Vlad [161]

Answer:

The Temperature in the afternoon was -4\° F.

Step-by-step explanation:

Given:

Temperature in the morning = -12\° F

Rise in temperature = 8\° F

We need to find the temperature in the afternoon.

Solution:

Now we know that;

temperature in the afternoon is equal to Temperature in the morning plus Rise in temperature in afternoon.

framing in equation form we get;

temperature in the afternoon = -12\° F+8\° F=-4\° F

Hence the Temperature in the afternoon was -4\° F.

3 0
2 years ago
ANSWER QUICK INSANELY EASY 4TH GRADE MATH EASY
stepan [7]

Answer: 40

Step-by-step explanation:

7 0
2 years ago
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