Common denominators for 14 and 710

Mathematics

1 answer:

Sunny_sXe [5.5K]3 years ago

6 0

Answer:

20 and 40

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What is the General form of the parabola of (y-3)^2=6(x+8)

MatroZZZ [7]

Answer:

x = 1.5 $t^{2}$ , y = 3 + 2at.

Step-by-step explanation:

For the parabola $Y^{2}$ = 4aX ,

General form will be

(X = a $t^{2}$ , Y = 2at) ,

Thus , for the parabola $(y-3)^{2}$ = 6(x +8)

Here , a = 1.5 and Y from the above equation should be substituted by y - 3 and X must be substituted by x + 8. After substitution of the same we can use the general equation formula for this parabola also.

Thus , general equation comes out to be :-

x + 8 = 1.5 $t^{2}$ , y - 3 = 2at

x = 1.5 $t^{2}$ , y = 3 + 2at.

4 0

3 years ago

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Feliz [49]

Answer:

The think that the answer is question 1 is B and the answer to question 2 is also B.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Does the point (-4, 2) lie inside or outside or on the circle x^2 + y^2 = 25?

stiv31 [10]

Given equation of the Circle is ,

$\sf\implies x^2 + y^2 = 25$

And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,

$\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2$

Here we can say that ,

• Radius = 5 units

• Centre = (0,0)

Finding distance between the two points :-

$\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }$