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blagie [28]
3 years ago
13

Common denominators for 14 and 710

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
6 0

Answer:

20 and 40

Please click the golden crown :)

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Teresa is factoring this polynomial by grouping. Which common factors should be used in the next step of factoring? 10x3 3x2−20x
Oksi-84 [34.3K]

Answer:

−2=−2x^3

Step-by-step explanation:

10x3= 3x2−20x−6=(10x3⋅(3x2))(−20x−6)=−600x6−180x5x2=−600x6−180x5−2x⋅(2x2)=−4x3−2x⋅x2=−2x^3

−2=−2x3

2x^2=−2x^3

−2=−2x^3

8 0
2 years ago
Read 2 more answers
Find the gain percent in the following:<br>Cost Price Rs 280,<br>(a) Selling Price<br>Rs 290​
Nikolay [14]

Answer:

3.57

Step-by-step explanation:

P=SP -CP

=290-280=10

P%=\frac{P*100}{CP}

=\frac{10*100}{280}

=\frac{1000}{280}

=3.57

4 0
3 years ago
How to know if a function is periodic without graphing it ?
zhenek [66]
A function f(t) is periodic if there is some constant k such that f(t+k)=f(k) for all t in the domain of f(t). Then k is the "period" of f(t).

Example:

If f(x)=\sin x, then we have \sin(x+2\pi)=\sin x\cos2\pi+\cos x\sin2\pi=\sin x, and so \sin x is periodic with period 2\pi.

It gets a bit more complicated for a function like yours. We're looking for k such that

\pi\sin\left(\dfrac\pi2(t+k)\right)+1.8\cos\left(\dfrac{7\pi}5(t+k)\right)=\pi\sin\dfrac{\pi t}2+1.8\cos\dfrac{7\pi t}5

Expanding on the left, you have

\pi\sin\dfrac{\pi t}2\cos\dfrac{k\pi}2+\pi\cos\dfrac{\pi t}2\sin\dfrac{k\pi}2

and

1.8\cos\dfrac{7\pi t}5\cos\dfrac{7k\pi}5-1.8\sin\dfrac{7\pi t}5\sin\dfrac{7k\pi}5

It follows that the following must be satisfied:

\begin{cases}\cos\dfrac{k\pi}2=1\\\\\sin\dfrac{k\pi}2=0\\\\\cos\dfrac{7k\pi}5=1\\\\\sin\dfrac{7k\pi}5=0\end{cases}

The first two equations are satisfied whenever k\in\{0,\pm4,\pm8,\ldots\}, or more generally, when k=4n and n\in\mathbb Z (i.e. any multiple of 4).

The second two are satisfied whenever k\in\left\{0,\pm\dfrac{10}7,\pm\dfrac{20}7,\ldots\right\}, and more generally when k=\dfrac{10n}7 with n\in\mathbb Z (any multiple of 10/7).

It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when k is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.

Let's verify:

\sin\left(\dfrac\pi2(t+20)\right)=\sin\dfrac{\pi t}2\underbrace{\cos10\pi}_1+\cos\dfrac{\pi t}2\underbrace{\sin10\pi}_0=\sin\dfrac{\pi t}2

\cos\left(\dfrac{7\pi}5(t+20)\right)=\cos\dfrac{7\pi t}5\underbrace{\cos28\pi}_1-\sin\dfrac{7\pi t}5\underbrace{\sin28\pi}_0=\cos\dfrac{7\pi t}5

More generally, it can be shown that

f(t)=\displaystyle\sum_{i=1}^n(a_i\sin(b_it)+c_i\cos(d_it))

is periodic with period \mbox{lcm}(b_1,\ldots,b_n,d_1,\ldots,d_n).
4 0
3 years ago
Plzzzz help meeeeeeeee 45 points ASAAAPPPPPPP
lubasha [3.4K]

Answer:

240

Step-by-step explanation:

If you draw a straight line, 12 would meet at 240. Hope this is helpful! You were close but I think you mixed up 240 and 300.

6 0
2 years ago
Read 2 more answers
Explain your answer !! <br> Have a nice day <br><br> Will give braisnlt
Viktor [21]

Answer:

(3,-4) or x=3 and y= -4

Step-by-step explanation:

I'm going to solve this by substitution

We first need to get a variable by itself in one of the two equations (it doesn't matter which variable and the equation you do the work on doesn't matter either)

I'm going to solve for y in the second equation

-4x-4y=4

add 4y and subtract 4 from both sides to get

-4x-4=4y

Divide by 4 to get

-x-1=y

We can plug this value in for y into the first equation and get

4x+5(-x-1)= -8

Solve for x

4x-5x-5= -8

-x-5= -8

-x= -3

x=3

We can plug this value into one of the first two equations and solve for y

4(3)+5y= -8

12+5y= -8

5y= -20

y= -4

Therefore the solution is (3,-4) or x=3 and y= -4

8 0
2 years ago
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