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grandymaker [24]
3 years ago
12

A store charges $56 for 5 pounds of crab meat. What is the unit price per pound of crab meat?

Mathematics
2 answers:
jeka57 [31]3 years ago
3 0
The unit price is 11.2
cupoosta [38]3 years ago
3 0

Answer:the unit price is 11.2

Step-by-step explanation:cuz u  divided 56 by 6 and u get =11.2 plz rate me brainest

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Solve the inequality and enter your solution as an inequality in the box below.
PSYCHO15rus [73]

Answer:

x > -10

Step-by-step explanation:

2 + x > -8

x > -8 - 2

x > -10

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2 years ago
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Mindy and Troy combined ate 99 pieces of the wedding cake. Mindy ate 3 pieces of cake and Troy had 1/4 of the total cake.
Allushta [10]

It doesn't give the entire question,  Do they want to know how many pieces were in the total cake?  If so, I think it would be 384.  You subtract the 3 pieces that Mindy ate and that leaves 96 that Tony had which was supposed to be 1/4 of the cake.  Dividing the cake into 4 sections of 96 and multiplying would give you 384.


If they want to know how many slices of cake were left after Tony ate the fourth (96 slices), it would be 288

3 0
3 years ago
Graph: Y – 3=1/2(x +2)
tatuchka [14]

Answer:

Step-by-step explanation:y–3=½(x+2)

Multiply through by the denominator (2).

2×y–2×3=½(x+2)×2

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2y–6=x+2

2y=x+2+6

2y=x+8

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2. 2

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-----. Or y=x+4

2

5 0
3 years ago
What is the value of \dfrac{d}{dx}\left(\dfrac{2x+3}{3x^2-4}\right) dx d ​ ( 3x 2 −4 2x+3 ​ )start fraction, d, divided by, d, x
stellarik [79]

Answer:

4.

Step-by-step explanation:

We are asked to find the value of expression \frac{d}{dx}(\frac{2x+3}{3x^2-4}) at x=-1.

First of all, we will find the derivative of the given expression using "Quotient Rule of Derivatives" as shown below:

(\frac{f(x)}{g(x)})'=\frac{f'(x)\cdot g(x)-f(x)\cdot g'(x)}{(g(x))^2}

\frac{d}{dx}(\frac{2x+3}{3x^2-4})

\frac{\frac{d}{dx}(2x+3)*(3x^2-4)-(2x+3)*\frac{d}{dx}(3x^2-4)}{(3x^2-4)^2}

\frac{2*(3x^2-4)-(2x+3)*(6x)}{(3x^2-4)^2}

\frac{6x^2-8-12x^2-18x}{(3x^2-4)^2}

\frac{-6x^2-18x-8}{(3x^2-4)^2}

Therefore, our required derivative is \frac{-6x^2-18x-8}{(3x^2-4)^2}.

Now, we will substitute x=-1 in our derivative to find the required value as:

\frac{-6(-1)^2-18(-1)-8}{(3(-1)^2-4)^2}

\frac{-6(1)+18-8}{(3(1)-4)^2}

\frac{-6+18-8}{(3-4)^2}

\frac{4}{(-1)^2}

\frac{4}{1}

4

Therefore, the value of expression \frac{d}{dx}(\frac{2x+3}{3x^2-4}) at x=-1 is 4.

6 0
3 years ago
Select the correct answer. Given the domain {-2, 2, 4}, what is the range for the relation 3x + y = 3?
ANEK [815]

Answer: {0, 5, 7}

Step-by-step explanation:

{0, 5, 7}

4 0
3 years ago
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