3 years ago

WILL BRAINLIEST!! Please help need 2,3,4

1 answer:

3 0

Equation of line parallel to y=5x+1 and containing the point (5,8)?

The slope of a line parallel to y=5x+1 would be 5. Parallel lines have the same slope.

Using the slope-intercept form of the eqn of a str line:

8 = 5(5) + b so 8 = 25 + b, and b = -17.

Thus, the desired equation is y = mx + b, or y = 5x - 17.

Check it! When x = 5, is y =8? 5(5)-17 = 25-17=8. YES

The slope of the line in #2 is 5. The slope of a line perpendicular to y = 5x - 17 is the negative reciprocal of 5:

m = -1/5 (answer).

Show me what you've done on #4, and then I'll get back to you with suggestions (if neeed).

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PLEASE HELP!!! i’ll give brainliest

tekilochka [14]

Answer:

x = $\sqrt{164$

Step-by-step explanation:

In order to find the hypothenuse, you need to do $8^{2} + 10^{2}$ . Which equals 164. Therefore, since $a^{2} +b^{2} =c^{2}$ , a=8, b=10, and c= $\sqrt{164$ .